Count number of letters in a range in array range

DougStroud

Well-known Member
Joined
Aug 16, 2005
Messages
2,976
Office Version
  1. 365
Platform
  1. MacOS
I cannot get this to work-
Code:
If Not IsError(Application.Match(c.Value, Array("SNBD", "SNBB", "SNBT", "SNBJ", "SNBP", "SNBGG", "SNBH", "SNBGL", "SNBPK", "SHOES", "HAT", "BEAN", "TEE"), 0)) _
And Len(Range(c.Offset(0, 55)).Value & Range(c.Offset(0, 56)).Value & Range(c.Offset(0, 57)).Value) < 1 Then

However- this does:
Code:
MsgBox Len(Range("BC6").Value & Range("BD6").Value & Range("BE6").Value)

Can you point out what is wrong for me in the first example please?

Posted here:
http://www.vbaexpress.com/forum/showthread.php?p=118251#post118251
 

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