njsutorius
New Member
- Joined
- Apr 6, 2014
- Messages
- 43
I would like to have a grade scale so that where c3 = wherever b3 falls in the range in column A.
Thus if B3 is 10 then C3 would equal 4.5 on the scale range.
We can breakout the range in A if needed into multiple columns if necessary.
[TABLE="class: outer_border, width: 500"]
<tbody>[TR]
[TD][/TD]
[TD]a
[/TD]
[TD]b
[/TD]
[TD]c
[/TD]
[/TR]
[TR]
[TD]1
[/TD]
[TD]1-5 = 0
[/TD]
[TD]CPH
[/TD]
[TD]Score
[/TD]
[/TR]
[TR]
[TD]3
[/TD]
[TD]6-8 = 3.5
[/TD]
[TD]10
[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]4
[/TD]
[TD]9-11 = 4.5
[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]5
[/TD]
[TD]12+ = 5
[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]6
[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]7
[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
</tbody>[/TABLE]
Thanks for any assistance.
Thus if B3 is 10 then C3 would equal 4.5 on the scale range.
We can breakout the range in A if needed into multiple columns if necessary.
[TABLE="class: outer_border, width: 500"]
<tbody>[TR]
[TD][/TD]
[TD]a
[/TD]
[TD]b
[/TD]
[TD]c
[/TD]
[/TR]
[TR]
[TD]1
[/TD]
[TD]1-5 = 0
[/TD]
[TD]CPH
[/TD]
[TD]Score
[/TD]
[/TR]
[TR]
[TD]3
[/TD]
[TD]6-8 = 3.5
[/TD]
[TD]10
[/TD]
[TD][/TD]
[/TR]
[TR]
[TD]4
[/TD]
[TD]9-11 = 4.5
[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]5
[/TD]
[TD]12+ = 5
[/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]6
[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]7
[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
</tbody>[/TABLE]
Thanks for any assistance.