Extracting Unique Records in a column

Baskar

New Member
Joined
Jul 31, 2013
Messages
14
Dear Friends,
AB
12AP
12AP
13CH
1CH
2CH
15CH
2AP

<COLGROUP><COL style="WIDTH: 48pt" span=2 width=64><TBODY>
</TBODY>

I have a scenerio where to extract unique records in a column on condition base. I have managed to
find unique base using {=INDEX($K$2:$K$8,MATCH(0,COUNTIF($C$1:C1,$A$2:$A$8),0))}.

To Find Unique base on condition I have tried {=INDEX($K$2:$K$8,MATCH(0,COUNTIFs($C$1:C1,$A$2:$A$8,$B$2:$B$8,"CH"),0))} but didn't worked.


Kindly Guide me where I went wrong.
 

Excel Facts

Formula for Yesterday
Name Manager, New Name. Yesterday =TODAY()-1. OK. Then, use =YESTERDAY in any cell. Tomorrow could be =TODAY()+1.
Try:

=INDEX(A$2:A$8,SMALL(IF(FREQUENCY(IF(B$2:B$8="CH",MATCH(A$2:A$8,A$2:A$8,0)),ROW(A$2:A$8)-ROW(A$2)+1),ROW(A$2:A$8)-ROW(A$2)+1),ROWS(C$2:C2)))

confirmed with Ctrl+Shift+Enter.
 
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