VBA code that needs restructuring

Estatefinds

Board Regular
Joined
Sep 14, 2015
Messages
169
I have a code that when run it will search for data from one column and searches for its match in numerous other columns; specifically every 8 columns where data is found and it returns the the row on which that matching data is found.
What i need is for someone to help me change the code so it will search in only one column and return the row it is found on.

(code)
sub my search()
For each gcell in Range("g1", range(G65536").End(xlup))
If isempty(cell(gcell.row, 8)) Then
For each c in Range ("Z1:AOOO324597")
I=Application.match(gcell.value, Range(c, Cells(324597, c.column)), 0)
if Not iserror(I) Then
Cells(gcell.row,8)=I
exit for
end if
next
if is empty(cells(gcell.row, 8)) then
cells(gcell.row, 8) ="$#N/A"
end if
end if
next
end sub
 
so What I am try to accomplish is instead of searching through the Z1 to AOO324597 the code will only search in the Z column. so Z1 through Z324597
 
Last edited:
Upvote 0

Excel Facts

Test for Multiple Conditions in IF?
Use AND(test, test, test, test) or OR(test, test, test, ...) as the logical_test argument of IF.
so What I am try to accomplish is instead of searching through the Z1 to AOO324597 the code will only search in the Z column. so Z1 through Z324597. so the code looks at column "G" then looks for the Matching data in column "Z" then it returns the row that the matching data was found within column Z.
 
Upvote 0
so What I am try to accomplish is instead of searching through the Z1 to AOO324597 the code will only search in the Z column. so Z1 through Z324597. so the code looks at column "G" then looks for the Matching data in column "Z" then it returns the row that the matching data was found within column Z.
 
Upvote 0
Don't have Excel at the moment....and still don't follow your code....but is this what you want...UNTESTED
Code:
Sub mysearch()
Dim lr As Long, c As Range
lr = Cells(Rows.Count, "G").End(xlUp).Row
For Each c In Range("G1:G" & lr)
If c.Value = "" Then c.Value = "#N/A"
I = Application.Match(c.Value, Range("Z1:Z" & lr), 0)
If Not IsError(I) Then c.Value = I
Next c
End Sub
 
Upvote 0
This code didn't work but I'll give an idea how the excel is set up.
Column G has numerical data. Column H is where the row is recorded, based on where each matching data is found on column Z. So the code will return the row on which data found on to column H and it will say "done" in column I. The original code would do a search every 8 columns where data was found but I placed it in one column for organization purposes and easier reading
 
Upvote 0
Try this:
Code:
Sub mysearch()
    Dim lr As Long
    Dim i As Long
    lr = Cells(Rows.Count, 7).End(xlUp).Row
    For i = 2 To lr
        If Not Cells(i, 7).Value = "" Then
            On Error Resume Next
            Cells(i, 8).Value = Columns(26).Find(What:=Cells(i, 7).Value, After:=Columns(26).Cells(1, 1), _
                LookIn:=xlValues, LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlPrevious, MatchCase:=True).Row
            On Error GoTo 0
            If Cells(i, 8).Value = "" Then Cells(i, 8).Value = "Not Found"
        End If
    Next i
End Sub
 
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