VBA needed to separate project from 1 worksheet to 3

marialewis16

New Member
Joined
Sep 22, 2023
Messages
2
Office Version
  1. 2019
Platform
  1. Windows
Hello,

I got a great little code from someone named BSB a couple of weeks ago on the other excel forum. However, I changed my project a little and need an adjustment to it that I can't seem to figure out.

His code worked perfectly for what I had asked for at the time. Basically I would like to enter a number into a cell and then that number of rows from the bottom of a Table would populate to the top of a Range in different columns. The code here does this well when everything is on one worksheet.

However, I need help separating the parts to different worksheets. I would like the Data Source Table to be on Sheet1, the input cell (where I would type in the number of rows I want) to be on Sheet2 and the Range where the rows are sent to would be on sheet3.

Also, I would like the new Range to actually be a Table and have the empty rows that you get when reducing the number in the input cell to be deleted. Hopefully that can be coded as well.

I appreciate any help you guys can give me, thank you so much!
-Maria

VBA Code:
Private Sub Worksheet_Change(ByVal Target As Range)
    Dim x As Long
    
    With ThisWorkbook.Sheets("Sheet1")
        Application.EnableEvents = False
        If Target.Cells.Count = 1 Then
            .Range("K2:N" & .Cells(Rows.Count, "K").End(xlUp).Row).ClearContents
            
            x = .Range("I3")
            .Range("K2").Resize(x, 4).Value = .ListObjects("Table1").Range(.ListObjects("Table1").ListRows.Count + 1, 1).Offset(-x + 1).Resize(x, 4).Value
        End If
        Application.EnableEvents = True
    End With
End Sub
 

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Cross posted at: Retrieve a specified number of rows from a Table
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Upvote 0
I am sorry, I thought these forums were completely separate. I was trying to increase my odds of getting a faster answer. Won't happen again, thanks for letting me know.
 
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They are completely different, that's why it's cross-posted. If you follow the link given in the rules & read what is said you would understand.
 
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This has now been marked as solved on EF
 
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