error.type #div/0! #div/0

  1. S

    Need help using ERROR.TYPE in an IF statement (not getting antipated result if the condition is false)

    Hello, I am trying to figure out why the formula's below work if the first condition is TRUE (in this case returns the ERROR.TYPE 2 for #DIV/0) the formula will return a "0" as requested (in Example A below); however, if the first condition of the if formula is FALSE it returns N/A? I have...
  2. S

    Need help using ERROR.TYPE in an IF statement (not getting antipated result if the condition is false)

    Hello, I am trying to figure out why the formula's below work if the first condition is TRUE (in this case returns the ERROR.TYPE 2 for #DIV/0) the formula will return a "0" as requested (in Example A below); however, if the first condition of the if formula is FALSE it returns N/A? I have...

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