concatenate text alternatively from 2 or more cells

mariusliviu

New Member
Joined
Jun 20, 2023
Messages
7
Office Version
  1. 365
  2. 2021
  3. 2019
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Hello, I hope this wasn't asked before, I've tried to search multiple ways...
Anyway, is it possible to create a formula or a VBA code that can do this (cells A and B have text, cell C should be the result):
1687298956760.png


The text in cells A and B have a line break (there are 3 rows but it can be more or less). In cell C it's done a concatenation of each line in the cell with a delimiter "|" between text in cell A and text in cell B and then a row break (char(10)) between each line in cell. The text could be only text or numbers, or symbols or a phrase...
I think it's clear enough from the image.
Is it possible to do with a formula or a macro (I prefer formula if it's easier)?

Thank you,
Marius
 
Space is a character.
I think I will leave it like this. Overall is what I wanted in the first place. There will be some individual cases on some cell but it's ok like this.
Thank you for your time and solution.
 
Upvote 0

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I am looking at it., but it's not immediately clear how do it with formulas.

It can be done with PowerQuery as well. Or, if like Tom was saying, you can go into the cells that are missing a row and just insert a space character and it should work as expected.
 
Upvote 0
How about this?

Book1
ABCD
5a b cd ea|d b|e c|
Sheet1
Cell Formulas
RangeFormula
D5D5=TEXTJOIN(CHAR(10),,LET(crc,LAMBDA(cel,LEN(cel)-LEN(SUBSTITUTE(cel,CHAR(10),""))+1),mx,MAX(SCAN(0,A5:B5,LAMBDA(s,c,crc(c)))),r,REDUCE("",A5:B5,LAMBDA(s,c,s&TEXTSPLIT(c&REPT(CHAR(10),mx-crc(c)),,CHAR(10))&"|")),LEFT(r,LEN(r)-1)))
 
Upvote 0
1687419436437.png
1687419500425.png
or
1687419539809.png

How about this?

Book1
ABCD
5a b cd ea|d b|e c|
Sheet1
Cell Formulas
RangeFormula
D5D5=TEXTJOIN(CHAR(10),,LET(crc,LAMBDA(cel,LEN(cel)-LEN(SUBSTITUTE(cel,CHAR(10),""))+1),mx,MAX(SCAN(0,A5:B5,LAMBDA(s,c,crc(c)))),r,REDUCE("",A5:B5,LAMBDA(s,c,s&TEXTSPLIT(c&REPT(CHAR(10),mx-crc(c)),,CHAR(10))&"|")),LEFT(r,LEN(r)-1)))
the result should be on the same line like in the pictures.
 
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