COUNTIFS that only counts Unique entries

RodneyW

Active Member
Joined
Sep 24, 2010
Messages
439
Office Version
  1. 2013
Platform
  1. Windows
I'm using this formula and it works exactly as designed.

=COUNTIFS($F$8:$F$10000,"*",$A$8:$A$10000,"*")

How can I modify it so that it only counts unique entries in column A.

Thanks in advance
 

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Since you don't have the Function Unique, I improvised by adding a helper column that counted the number of occurrences of each item in column A: B8=COUNTIF(A$8:A8,A8)

Then I could one more criteria in your formula: =COUNTIFS($F$8:$F$10000,"*",$A$8:$A$10000,"*",$B$8:$B$10000,1)
 
Upvote 0
Or, without a helper column...

Excel Formula:
=SUM(IF(FREQUENCY(IF(ISTEXT(A8:A10000),IF(ISTEXT(F8:F10000),MATCH("~"&A8:A10000&"|"&F8:F10000,A8:A10000&"|"&F8:F10000&"",0))),ROW(A8:A10000)-ROW(A1)+1)>0,1))

Note that the formula will take into consideration formula blanks ( "" ), just like your original formula.

Hope this hleps!

Edited

The formula needs to be confirmed with CONTROL+SHIFT+ENTER, not just ENTER.
 
Last edited:
Upvote 0
Solution
Or, without a helper column...

Excel Formula:
=SUM(IF(FREQUENCY(IF(ISTEXT(A8:A10000),IF(ISTEXT(F8:F10000),MATCH("~"&A8:A10000&"|"&F8:F10000,A8:A10000&"|"&F8:F10000&"",0))),ROW(A8:A10000)-ROW(A1)+1)>0,1))

Note that the formula will take into consideration formula blanks ( "" ), just like your original formula.

Hope this hleps!
I'm getting a #VALUE! error. In this formula, what is expected to be in cell A1?
 
Upvote 0
Sorry, I forgot to mention that you need to confirm the formula with CONTROL+SHIFT+ENTER, not just ENTER. And, it should return a unique count of text values, including formua blanks ( "" ).
 
Upvote 0
Sorry, I forgot to mention that you need to confirm the formula with CONTROL+SHIFT+ENTER, not just ENTER. And, it should return a unique count of text values, including formua blanks ( "" ).
CONTROL+SHIFT+ENTER worked perfectly. Thank you
 
Upvote 0
Since you don't have the Function Unique, I improvised by adding a helper column that counted the number of occurrences of each item in column A: B8=COUNTIF(A$8:A8,A8)

Then I could one more criteria in your formula: =COUNTIFS($F$8:$F$10000,"*",$A$8:$A$10000,"*",$B$8:$B$10000,1)
Thanks for the reply. I just got all of the replies here and I started with the other one and it worked perfectly
 
Upvote 0

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