How do I fix this code

Macro_Nerd99

Board Regular
Joined
Nov 13, 2021
Messages
61
Office Version
  1. 365
I found this formula online that works great to extract a 6 digit code from a cell string: =MID(A1,MIN(FIND({0,1,2,3,4,5,6,7,8,9},A1&1234567890)),6)

However, I'm trying to use it in VBA code and extract it from a variable instead.
However, I get a syntax error when attempting this. How do I fix it?

Public Function Employee_ID() As String
Employee_ID =MID(thisworkbook.name,MIN(FIND({0,1,2,3,4,5,6,7,8,9},thisworkbook.name&1234567890)),6)
End Function
 

Excel Facts

How to find 2nd largest value in a column?
MAX finds the largest value. =LARGE(A:A,2) will find the second largest. =SMALL(A:A,3) will find the third smallest
How about
Excel Formula:
Public Function Employee_ID() As String
Employee_ID = Evaluate("MID(" & ThisWorkbook.Name & ",MIN(FIND({0,1,2,3,4,5,6,7,8,9}," & ThisWorkbook.Name & "&1234567890)),6)")
End Function
 
Upvote 0
How about
Excel Formula:
Public Function Employee_ID() As String
Employee_ID = Evaluate("MID(" & ThisWorkbook.Name & ",MIN(FIND({0,1,2,3,4,5,6,7,8,9}," & ThisWorkbook.Name & "&1234567890)),6)")
End Function
I get a "Type mismatch" runtime error
 
Upvote 0
Oops. forgot the extra quotes, try
VBA Code:
Public Function Employee_ID() As String
Employee_ID = Evaluate("MID(""" & ThisWorkbook.Name & """,MIN(FIND({0,1,2,3,4,5,6,7,8,9},""" & ThisWorkbook.Name & """&1234567890)),6)")
End Function
 
Upvote 0
Solution
Oops. forgot the extra quotes, try
VBA Code:
Public Function Employee_ID() As String
Employee_ID = Evaluate("MID(""" & ThisWorkbook.Name & """,MIN(FIND({0,1,2,3,4,5,6,7,8,9},""" & ThisWorkbook.Name & """&1234567890)),6)")
End Function
Now I get an "overflow" error. Thanks for your quick replies.
 
Upvote 0
You're welcome & thanks for the feedback.
 
Upvote 0

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