Min IFs not working

dmj120

Active Member
Joined
Jan 5, 2010
Messages
286
Office Version
  1. 365
  2. 2019
  3. 2010
I have a somewhat large data set that I've pivoted (a concat of three nomenclature columns) - data set is 80k rows, pivoted concat is only 28k rows. I'm trying to find the minimum, medium, and max prices.


I've tried both these, each gives a value error:
{=MIN(IFS('rptPricePoints'!$C:$C,$A4,'rptPricePoints'!$K:$K,">"&$B$1))}
{=MIN(IFS(rptPricePoints!$C:$C,$A7,rptPricePoints!$K:$K,">"&$B$1))}

'rptPricePoints'!$C:$C,$A4 = the concatenated nomenclature
'rptPricePoints'!$K:$K,">"&$B$1 = the minimum price of $14

The median and max formulas will be similar.
I get a value error with: {=MEDIAN(IF(rptPricePoints!$C:$C,A4,rptPricePoints!$K:$K))}

Where am I making a mistake?

Thanks
Josh
 

Excel Facts

Select a hidden cell
Somehide hide payroll data in column G? Press F5. Type G1. Enter. Look in formula bar while you arrow down through G.
Ok... I found a dumb mistake: =MIN(IF(rptPricePoints!$C:$C=$A4,IF(rptPricePoints!$K:$K,">"&$B$1,rptPricePoints!$K:$K))) which gets rid of the error, but results in a '0'
 
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