Remove 2 Lowest Numbers from a Sum of Numbers in Non-Consecutive Cells

thebrtnder

New Member
Joined
Apr 21, 2023
Messages
2
Office Version
  1. 365
Platform
  1. Windows
I cannot figure a way to remove the two lowest numbers from this sum of cells
For the lowest number I use the MIN function like this:
SUM(B6,B10,B14,B18,B22,B26,B30,B34)-MIN(B6,B10,B14,B18,B22,B26,B30,B34)
I dont believe the SMALL function works since the group of cells is not an array, so I am lost...
 

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Select range. Press Ctrl+1. On Number tab, choose Custom. Type Alt+7 then space then @ sign (using 7 on numeric keypad)
Welcome to the forum.
Try:
=SUM(B6,B10,B14,B18,B22,B26,B30,B34)-SUM(SMALL((B6,B10,B14,B18,B22,B26,B30,B34),{1,2}))
 
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Solution
Welcome to the forum.
Try:
=SUM(B6,B10,B14,B18,B22,B26,B30,B34)-SUM(SMALL((B6,B10,B14,B18,B22,B26,B30,B34),{1,2}))
Worked perfectly - thanks so much!!! So apparently an array can be created by putting the calls into parentheses - good to know!!! That was what I really couldn’t figure out… thanks again!
 
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Worked perfectly - thanks so much!!!
Welcome to the MrExcel board!
The marked solution has been changed accordingly. In your future questions, please mark the post as the solution that actually answered your question, instead of your feedback message as it will help future readers. No further action is required for this thread.

BTW, if you have all the new functions available in your 365 version, another option might be as shown in E6 below.

23 04 21.xlsm
BCDE
631313
75
86
90
102
116
125
133
141
151
164
177
182
195
206
214
222
233
245
256
262
275
284
296
302
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321
333
342
Sum less 2
Cell Formulas
RangeFormula
D6D6=SUM(B6,B10,B14,B18,B22,B26,B30,B34)-SUM(SMALL((B6,B10,B14,B18,B22,B26,B30,B34),{1,2}))
E6E6=SUM(DROP(SORT(CHOOSEROWS(B6:B34,SEQUENCE(8,,,4))),2))
 
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