assigning letters to unknown # of entries

almagg

Well-known Member
Joined
Aug 21, 2002
Messages
705
i have this list and the values that start with "NT" do not get counted.
and this is what they wanted originally and i had on the report.
now they want another column with letters assigned to all of the entries.
how would i deal with these letters? i am assuming it will involve ASCI characters but i never know how long the list will be and could possibly go into double letters(though it would not be monstrously long - the longest i see so far goes up to "U")


A_______NT#####
B___1___B####
C___2___A####
D_______NT#####
E___3___B####

thanks.
 

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BrianB

Well-known Member
Joined
Feb 17, 2003
Messages
8,127
Don't know what you want really.
If you just want to get the first letter into another column something like

=LEFT(A1,1)
 

crimson_b1ade

Well-known Member
Joined
Sep 27, 2008
Messages
1,557
maybe try (note: only works up to "IV" (that's only 256 rows). hopefully your list isn't that long):

=IF(ROW(A1)<=26,LEFT(ADDRESS(1,ROW(A1),4),1),LEFT(ADDRESS(1,ROW(A1),4),2))
 
Last edited:

crimson_b1ade

Well-known Member
Joined
Sep 27, 2008
Messages
1,557
here's another one which goes to "ZZ" (which equates to 754 rows of data):

Code:
=IF(ROW(A1)<=26,LOOKUP(ROW(A1),{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26;"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"}),LOOKUP(IF(ROUND((ROW(A1)/26-ROUNDDOWN(ROW(A1)/26,0))*26,0)=0,ROUNDDOWN(ROW(A1)/26,0)-1,ROUNDDOWN(ROW(A1)/26,0)),{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26;"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"})&LOOKUP(IF(ROUND((ROW(A1)/26-ROUNDDOWN(ROW(A1)/26,0))*26,0)=0,26,ROUND((ROW(A1)/26-ROUNDDOWN(ROW(A1)/26,0))*26,0)),{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26;"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"}))
 

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