average numbers that are greater than zero

singlgl1

Board Regular
Joined
Jan 13, 2007
Messages
127
I have a formula in place currently that is averaging a cell from 30 sheets, but I would like to only average those numbers that are greater than zero.How can I edit the current formula(below) to accomplish this? Thanks!

=AVERAGE('Apr. 01-07:Apr. 30-07'!B8)
 

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=SUM(Apr. 01-07:Apr. 30-07'!B8)/COUNTIF(Apr. 01-07:Apr. 30-07'!B8, ">0")

Perhaps, It's not tested so apologies if it doesn't work

Dave
 
Upvote 0
I have a formula in place currently that is averaging a cell from 30 sheets, but I would like to only average those numbers that are greater than zero.How can I edit the current formula(below) to accomplish this? Thanks!

=AVERAGE('Apr. 01-07:Apr. 30-07'!B8)

If you have the free morefunc.xll add-in installed...

=SUM('Apr. 01-07:Apr. 30-07'!B8)/MAX(1,COUNTIF.3D('Apr. 01-07:Apr. 30-07'!B8,">0"))
 
Upvote 0
=SUM(Apr. 01-07:Apr. 30-07'!B8)/COUNTIF(Apr. 01-07:Apr. 30-07'!B8, ">0")

Perhaps, It's not tested so apologies if it doesn't work

Dave

Only the OP knows for sure, but if some of his or hers values are LESS than zero, then the formula should be:

Code:
 =SUMIF(Apr. 01-07:Apr. 30-07'!B8,">0")/COUNTIF(Apr. 01-07:Apr. 30-07'!B8, ">0")
 
Upvote 0
=SUM(Apr. 01-07:Apr. 30-07'!B8)/COUNTIF(Apr. 01-07:Apr. 30-07'!B8, ">0")

Perhaps, It's not tested so apologies if it doesn't work

Dave

Only the OP knows for sure, but if some of his or hers values are LESS than zero, then the formula should be:

Code:
 =SUMIF(Apr. 01-07:Apr. 30-07'!B8,">0")/COUNTIF(Apr. 01-07:Apr. 30-07'!B8, ">0")

Excel's CountIf is not a 3D function...
 
Upvote 0
=SUM(Apr. 01-07:Apr. 30-07'!B8)/COUNTIF(Apr. 01-07:Apr. 30-07'!B8, ">0")

Perhaps, It's not tested so apologies if it doesn't work

Dave

Only the OP knows for sure, but if some of his or hers values are LESS than zero, then the formula should be:

Code:
 =SUMIF(Apr. 01-07:Apr. 30-07'!B8,">0")/COUNTIF(Apr. 01-07:Apr. 30-07'!B8, ">0")

Excel's CountIf is not a 3D function...

I didn't realize that the range being used was more than one dimension. I guess the . should have been the clue? :oops:
 
Upvote 0

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