Excel Calculate Compounded Growth Rate

ziad alsayed

Well-known Member
Joined
Jul 17, 2010
Messages
665
dear all

i am trying to calculate the Compounded Growth rate over for year. i am doing it by month through out the year.

the problem i am facing is that if the sales of last year is less than the sales of first year the below formual will not work .

i am not even sure i am getting the right result when sales of last year is higher than first year

appreciate any help.
Excel Workbook
ABC
12007 Figures19,000,00019,000,000
22008 Figures18,000,00018,000,000
32009 Figures14,000,00014,000,000
42010 Figures13,000,00019,500,000
5Compounded growth Rate#NUM!2559.15%
Sheet1
Excel 2010
Cell Formulas
RangeFormula
B5=(B4-B1)^(1/4)-100%
C5=(C4-C1)^(1/4)-100%
 

Excel Facts

Enter current date or time
Ctrl+: enters current time. Ctrl+; enters current date. Use Ctrl+: Ctrl+; Enter for current date & time.
If you want the exponential trend,

Code:
      --A--- -----B----- -----C-----
  1   FY2007 19,000,000  19,000,000 
  2   FY2008 18,000,000  18,000,000 
  3   FY2009 14,000,000  14,000,000 
  4   FY2010 13,000,000  19,000,000 
  5   Growth      -13.0%       -2.5%

B4 and across: =LOGEST(B1:B4) - 1
 
Upvote 0
dear shg4421 and Scott R, thanks for your reply.

now i am totally lost :)

both formula are logig ,but i am not getting the same result.

please check below and advise
Excel Workbook
ABC
1200719,000,000.0019,000,000.00
2200818,000,000.0018,000,000.00
3200914,000,000.0014,000,000.00
4201013,000,000.0019,000,000.00
5Scott R-11.88%0.00%
6shg4421-12.98%-2.48%
Sheet1
Excel 2010
Cell Formulas
RangeFormula
B5=(B4/B1)^(1/3)-1
B6=LOGEST(B1:B4)-1
C5=(C4/C1)^(1/3)-1
C6=LOGEST(C1:C4)-1
 
Upvote 0
One ignores the interior values of the series and just looks at the end points. The other is the slope of a best-fit exponential trendline through the data.
 
Upvote 0
thanks it is now clear,
i will go with your formula , i think it is more accurate.

thanks again for you and for Scott R for your your help.
 
Upvote 0
Scott's is no less accurate, it just measures something different. You should use the one that makes sense for the question you're trying to answer.
 
Upvote 0

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