fill down with in 'jumps'?

excelNewbie22

Well-known Member
Joined
Aug 4, 2021
Messages
510
Office Version
  1. 365
Platform
  1. Windows
hi!

how can i fill down this formula with jumps of rows? (don't know how phrase it so i called it jumps)
so the next formula will applied on a4:f4
than on a5:f5
and so on...

test
ABCDEFGHI
1
21234561-2-3-4-5
33567891-2-3-4-6
41112131415161-2-3-5-6
51415161718191-2-4-5-6
61-3-4-5-6
72-3-4-5-6
83-5-6-7-8
93-5-6-7-9
103-5-6-8-9
113-5-7-8-9
123-6-7-8-9
135-6-7-8-9
14
15
test
Cell Formulas
RangeFormula
I2:I7I2=LET(d,TOROW(A2:F2,1,1),N,5,c,COUNT(d),x,BYROW(IF(MOD(INT(SEQUENCE(2^c,,0)/2^SEQUENCE(,c,0)),2),d,""),LAMBDA(r,IF(COUNT(r)=N,TEXTJOIN("-",,r),""))),FILTER(x,x<>""))
I8:I13I8=LET(d,TOROW(A3:F3,1,1),N,5,c,COUNT(d),x,BYROW(IF(MOD(INT(SEQUENCE(2^c,,0)/2^SEQUENCE(,c,0)),2),d,""),LAMBDA(r,IF(COUNT(r)=N,TEXTJOIN("-",,r),""))),FILTER(x,x<>""))
Dynamic array formulas.
 

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found an alternative solution, adding a transpose to the formula, then fill down, and then joining all to one column
thanks any way!
 
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