Find Groups and Highlight them

motilulla

Well-known Member
Joined
Feb 13, 2008
Messages
2,362
Office Version
  1. 2010
Using Excel 2010

I have some set of 6 numbers in the range A2:F24 I want to find groups of consecutive numbers (2, 3, 4, 5 and 6) in the range H2:L2 and then highlight groups in different colours in the range A2:F24. Need a VBA solution.

n1n2n3n4n5n6Count Consequtives Group of 2 NumbersCount Consequtives Group of 3 NumbersCount Consequtives Group of 4 NumbersCount Consequtives Group of 5 NumbersCount Consequtives Group of 6 Numbers
1​
2​
3​
4​
5​
6​
1
1​
2​
10​
12​
22​
35​
1
1​
2​
3​
34​
36​
38​
1
1​
8​
20​
24​
33​
35​
1​
10​
14​
24​
28​
35​
1​
11​
16​
17​
29​
33​
1
2​
12​
33​
34​
35​
36​
1
14​
15​
18​
19​
34​
35​
3
16​
17​
18​
22​
23​
24​
2
2​
19​
20​
21​
22​
36​
1
4​
27​
29​
31​
36​
38​
5​
7​
10​
17​
21​
32​
5​
7​
15​
16​
17​
39​
1
6​
8​
12​
18​
20​
27​
8​
9​
10​
22​
24​
36​
1
8​
10​
16​
25​
26​
39​
1
8​
11​
17​
20​
22​
34​
8​
9​
10​
11​
12​
37​
1
12​
19​
23​
28​
36​
39​
13​
16​
25​
28​
36​
38​
16​
19​
28​
30​
31​
38​
1
17​
21​
26​
27​
34​
36​
1
18​
34​
35​
36​
37​
39​
1

Regards,
Moti
 

Excel Facts

Copy formula down without changing references
If you have =SUM(F2:F49) in F50; type Alt+' in F51 to copy =SUM(F2:F49) to F51, leaving the formula in edit mode. Change SUM to COUNT.
Hello, good morning here is an image attached for more in detailed in column A to F in each row there is set of 6 numbers. I want to get count of consecutive occurrences of numbers in the column H to L

And also VBA highlight the consecutive groups (2, 3, 4, 5 and 6) in the column A:F as shown in the image.

Regards,
Moti
 

Attachments

  • Groups.png
    Groups.png
    31.6 KB · Views: 12
Upvote 0
Hello, I have some set of 6 numbers in the range A2:F24 I want to find groups of consecutive numbers (2, 3, 4, 5 and 6) in the range H2:L2 and then highlight groups in different colors in the range A2:F24. Need a VBA solution.

If the highlight groups is not possible with VBA please help to count only consecutive groups in the range H2:L2.

Thank you all in advance

Regards,
Moti
 
Upvote 0
Please May be formula if VBa is not vaiable and CF for consecutive groups
 
Upvote 0
Give this a try.

VBA Code:
Sub Count_Groups()
  Dim a As Variant, b As Variant
  Dim r As Long, c As Long, i As Long, j As Long, k As Long, Clr As Long
  
  Clr = 5
  With Range("A2", Range("F" & Rows.Count).End(xlUp))
    .Font.ColorIndex = 0
    a = .Value
    ReDim b(1 To UBound(a), 2 To 6)
    For r = 1 To UBound(a)
      k = 1
      For c = 2 To 6
        If a(r, c) = a(r, c - 1) + 1 Then
          k = k + 1
        ElseIf k > 1 Then
          b(r, k) = b(r, k) + 1
          Clr = 8 - Clr
          For j = 1 To k
            .Cells(r, c - j).Font.ColorIndex = Clr
          Next j
          k = 1
        End If
      Next c
      If k > 1 Then
        b(r, k) = b(r, k) + 1
        Clr = 8 - Clr
        For j = 1 To k
          .Cells(r, c - j).Font.ColorIndex = Clr
        Next j
      End If
    Next r
  End With
  Range("H2:L2").Resize(UBound(b)).Value = b
End Sub

My worksheet before the code:

motilulla.xlsm
ABCDEFGHIJKL
1n1n2n3n4n5n6Groups of 2Groups of 3Groups of 4Groups of 5Groups of 6
2123456
31210122235
4123343638
51820243335
611014242835
711116172933
821233343536
9141518193435
10161718222324
1121920212236
1242729313638
135710172132
145715161739
156812182027
168910222436
1781016252639
1881117202234
198910111237
20121923283639
21131625283638
22161928303138
23172126273436
24183435363739
Sheet1



After:

motilulla.xlsm
ABCDEFGHIJKL
1n1n2n3n4n5n6Groups of 2Groups of 3Groups of 4Groups of 5Groups of 6
21234561
312101222351
41233436381
51820243335
611014242835
7111161729331
8212333435361
91415181934353
101617182223242
11219202122361
1242729313638
135710172132
1457151617391
156812182027
1689102224361
17810162526391
1881117202234
1989101112371
20121923283639
21131625283638
221619283031381
231721262734361
241834353637391
Sheet1
 
Upvote 1
Cheers. Glad it helped. :)

It will not do any harm but after testing the code I did not need the variable "i" so should have removed that declaration from the code but forgot. You can remove it if you want.
Rich (BB code):
Dim r As Long, c As Long, i As Long, j As Long, k As Long, Clr As Long
 
Upvote 1
Happened to be looking back over this code and noticed some other simplifications/shortening that could be applied if you want to try this version.

VBA Code:
Sub Count_Groups_v2()
  Dim a As Variant, b As Variant
  Dim r As Long, c As Long, k As Long, Clr As Long
  
  Clr = 5
  With Range("A2", Range("F" & Rows.Count).End(xlUp))
    .Font.ColorIndex = 0
    a = .Value
    ReDim b(1 To UBound(a), 2 To UBound(a, 2))
    ReDim Preserve a(1 To UBound(a), 1 To UBound(a, 2) + 1)
    For r = 1 To UBound(a)
      k = 1
      For c = 2 To UBound(a, 2)
        If a(r, c) = a(r, c - 1) + 1 Then
          k = k + 1
        ElseIf k > 1 Then
          b(r, k) = b(r, k) + 1
          Clr = 8 - Clr
          .Cells(r, c - k).Resize(, k).Font.ColorIndex = Clr
          k = 1
        End If
      Next c
    Next r
  End With
  Range("H2").Resize(UBound(b), UBound(b, 2) - 1).Value = b
End Sub
 
Upvote 1
Solution
Happened to be looking back over this code and noticed some other simplifications/shortening that could be applied if you want to try this version.
Peter, I appreciate your help, great of you for making shooter and better version. defiantly I am using this one. (y)

Good Luck forever!

My Best Regards,
Moti :)
 
Upvote 0

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