Find number after specific letter in cell

enigma04

New Member
Joined
Mar 1, 2011
Messages
37
Hi,

Is there a formula or vb code i can use to find a numbers after a specific letter in a cell no matter where that letter is in the cell?

Example: G0Z-1.4743Y1.2479X2..... I would like to find the 1.2479 after the "y" and use it in a formula. My goal is to find that number, divide it by .0076358155 and replace the existing number with the answer. Is this possible?

Thanks,

Kevin
 

Excel Facts

Will the fill handle fill 1, 2, 3?
Yes! Type 1 in a cell. Hold down Ctrl while you drag the fill handle.
Hello Kevin, welcome to MrExcel

Will the number always be 6 characters, including the decimal point? What about the new number should that take up the same number of characters?
 
Upvote 0
The number should always be 6 characters including the decimal point but will not always be followed by an "x"...


Examples:
Z-1.3545Y1.6564
Z-1.3535Y1.2734F12.00
G0Z-1.4743Y1.2479X2.
 
Upvote 0
The FIND function is case sensitive. Try this...
=MID(A1,FIND("Y",A1)+1,6)/0.0076358155

Or use the SEARCH function (not case sensitive)...
=MID(A1,SEARCH("y",A1)+1,6)/0.0076358155
 
Last edited:
Upvote 0
Try this formula to extract the value, do the calculation and then replace it.......

=REPLACE(A1,FIND("Y",A1)+1,6,LEFT(TEXT(MID(A1,FIND("Y",A1)+1,6)/0.0076358155,"0.00000"),6))
 
Upvote 0
I'm sure this can be tidied up but in vba it can be done something like this



Code:
Sub Number_Replacer()

Dim StrLen, j As Integer
Dim i, FirstPart, SecondPart, ThirdPart As String
Dim Divi, divfig As Double
    i = ActiveCell.Value
    j = InStr(1, i, "Y", vbTextCompare)
    StrLen = Len(i)
    divfig = 0.0076358155
        
        FirstPart = Left(i, j)
    
        SecondPart = Left(Right(i, StrLen - j), 6)
    
        ThirdPart = Right(i, StrLen - j - 6)
   
        Divi = CDbl(SecondPart)
        Divi = Divi / divfig
    
    ActiveCell.Offset(0, 1).Value = FirstPart & Divi & ThirdPart

End Sub
 
Last edited:
Upvote 0

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