Finding the Number of Columns Between Two Values

dskexcel

New Member
Joined
Mar 4, 2015
Messages
48
Hello,

I need to find the number of cells between the second and third values. Below is an example:

ABCDEFGH
5215
899

<tbody>
</tbody>

So, for row 2, I'd like the formula to return an answer of 3. For row 3, I'd like it to return 2. I have two other columns that help a little by providing the values of the second and third values (for instance I2 would show "2" and J2 shows 15). With these extra columns that identify the second and third values, I used this formula with some success: =ABS(MATCH(I2, (A2:H2, 0)-MATCH(J2, A2:H2, 0)).

However, that formula does not work with A3:H3 from my example. The reason is because the second and third values are the same (9 and 9), therefore cells I3 and J3 are the same.

Thanks in advance!
 
Last edited:

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RickXL

MrExcel MVP
Joined
Sep 9, 2013
Messages
4,325
Hi,

I can do a VBA User-Defined Function. Any good?

Paste the following code into a new Module then you will have a new worksheet function called Test. Just give Test the range to be examined. For example:
=Test(A1:H1)
then drag the formula down.

Code:
Function Test(r As Range) As Variant
    Dim i As Long
    Dim bln1 As Boolean
    Dim col2 As Long
    For i = 1 To r.Count
        If r(1, i).Value <> "" Then
            If col2 > 0 Then
                Test = i - col2
                Exit Function
            End If
            If bln1 And col2 = 0 Then col2 = i
            If Not bln1 Then bln1 = True
        End If
    Next
    Test = CVErr(xlErrNA)
End Function
 

Scott Huish

MrExcel MVP
Joined
Mar 17, 2004
Messages
19,958
Office Version
  1. 365
  2. 2010
Platform
  1. Windows
Perhaps:

=SUM(SMALL(IF(ISNUMBER(A1:H1),COLUMN(A1:H1)),{3,2})*{1,-1})

Confirm with CTRL-SHIFT-ENTER rather than just Enter
 
Last edited:

RickXL

MrExcel MVP
Joined
Sep 9, 2013
Messages
4,325
It looks good to me, Scott.

I thought Arrays, I could visualize a list of Trues and Falses ...
Then I ran out of brain-power. :)

I really must get the hang of this worksheet stuff!

Neat solution.

Regards,
 

dskexcel

New Member
Joined
Mar 4, 2015
Messages
48
Thank you both for the solutions! Rick, I'm not a VBA guy so I'm going to use Scott's solution, but thanks for the efforts.

Scott - your formula works great, thanks!
 

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