How to find and truncate text after the first space before the 38th character

Seric

New Member
Joined
Feb 21, 2019
Messages
10
Office Version
  1. 365
Platform
  1. Windows
I am trying to write either a formula or Macro to find the last space in a string before the 38th character. My problem is that my data is not standard and I don't want to truncate in the middle of a word that falls at 37 characters. See example below.

Free-bird Real Opportunities And Encyclopedias LLP = 50 Char

Free-bird Real Opportunities And Ency = 37 char truncation

The goal would look like the truncation below where Encyclopedias is not cut in the middle.

Goal = Free-bird Real Opportunities And

Subsequently I will need to pull out the remaining portion of the name (Encyclopedias LLP) into a different cell.


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Hi & welcome to MrExcel.
How about
Code:
Sub Seric()
   Dim a As Long
   Dim V As String
   V = Range("J2").Value
   a = InStrRev(V, " ", 38)
   Range("K2") = Left(V, a - 1)
   Range("L2") = Right(V, Len(V) - a)
End Sub
Change ranges to suit
 
Upvote 0
Or with formulas:

A
1Free-bird Real Opportunities And Encyclopedias LLP
2
3Free-bird Real Opportunities And
4Encyclopedias LLP

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Sheet12


Worksheet Formulas
CellFormula
A4=TRIM(MID(A1,LEN(A3)+1,LEN(A1)))

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</tbody>

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Array Formulas
CellFormula
A3{=IF(LEN(A1)<38,A1,LEFT(A1,MAX(IF(MID(A1,ROW(INDIRECT("2:38")),1)=" ",ROW(INDIRECT("1:37"))))))}

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Entered with Ctrl+Shift+Enter. If entered correctly, Excel will surround with curly braces {}.
Note: Do not try and enter the {} manually yourself

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Last edited:
Upvote 0
This is FABULOUS, thank you!

I modified my code to find the values in the entire column that I need to analyse, but the debugger is getting caught by the cell's who's length is less that 38 already. Suggestions?

Sub Seric()
Dim a As Long
Dim V As String

For i = 2 To 161

V = Cells(i, "B").Value
a = InStrRev(V, " ", 38)

Cells(i, "C") = Left(V, a - 1)
Cells(i, "D") = Right(V, Len(V) - a)

Next i
End Sub
 
Upvote 0
How about
Code:
Sub Seric()
   Dim a As Long, i As Long
   Dim V As String
   
   For i = 2 To 161
      If Len(Cells(i, "B")) < 39 Then
         Cells(i, "C") = Cells(i, "B")
      Else
         V = Cells(i, "B").Value
         a = InStrRev(V, " ", 38)
         
         Cells(i, "C") = Left(V, a - 1)
         Cells(i, "D") = Right(V, Len(V) - a)
      End If
   Next i
End Sub
 
Upvote 0

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