LEAP YEAR

HighlandPiper

New Member
Joined
Apr 28, 2016
Messages
19
Good afternoon all

Should my excel spreadsheet automatically identify 2024 as a leap year? It doesn't!

Let me expand on that. I have a lookup table that will calculate 36 months based on the start date.

Example
Manual input - Start Date: 02/02/2024
Formula - End Date: 02/02/2027

I am also using an online platform and when I enter the start date of 02/02/2024 the result is 03/02/2027
 

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Yes Excel does know that 2024 is a leap year. What makes you think it doesn't?
 
Upvote 0
To prove that Excel recognizes the Leap Year, enter 2/2/24 in cell A1, then enter this formula in cell B1:
Excel Formula:
=A1+27
You can see that it returns 2/29/24

If you are trying to do date math where you are adding months or years to a date, it will ignore the day part and always return the same day, i.e.
regardless of whether or not there is a leap year, adding exactly 3 years to the date 2/2/24 is 2/2/27.

If you want it to be 2/1/27, you would need to add days, not months or years, i.e.
Excel Formula:
=A1+(365*3)
 
Upvote 0
I would add months, but I would use EDATE to get it:

=EDATE(B1,36)
Scott, that might be what they are using now, and if I understand it correctly, I think that is precisely what they are saying the problem is.
That formula would return 2/2/2027.

But if I am understanding it correctly, I think they are expecting wanting 2/1/2027 (because this year is a Leap Year, they are wanting one day earlier on the final date).
If their intention is to return 2/1/2027 and not 2/2/2027, they could not use a method like this that adds months or years, but would rather have to use one that add days, like I showed.

Based on the original question, that is my best guess, but I could be completely wrong, as they have not shown us the formula that they are currently using.
 
Upvote 0
But 365 isn't exactly accurate either. The 2nd example said they got a date of March 2, 2027 which made no sense at all to me.

This might be a little closer though:
=B1+(365.25*3)

If they decided they want 4 years instead of 3, your formula wouldn't give the result I would expect

Book1
ABCD
1Manual input - Start Date2/29/20242/28/20282/29/2028
2Formula - End Date2/28/2027
Sheet1
Cell Formulas
RangeFormula
C1C1=B1+(365*4)
D1D1=B1+(365.25*4)
B2B2=EDATE(B1,36)




EDATE doesn't always return the same day though.

If you do an EDATE on 2/29/24 with 36 month, it doesn't return March 1 which would technically be an equivalent day, It returns 2/28 since it's not a leap year
 
Upvote 0
But 365 isn't exactly accurate either. The 2nd example said they got a date of March 2, 2027 which made no sense at all to me.

This might be a little closer though:
=B1+(365.25*3)
I may have misunderstood what there question/end goal is. Without seeing their formula it is hard to tell.
Upon further review and looking back at the question, it looks like maybe 2/2/2027 is the desired goal, but they are getting 3/2/2027 (I missed that date at first, as being in the US, our date formats are m/d/yyyy, and I was focusing on the second number of 2 instead of the first number of 3).

So I am thinking that you are probably correct, and if 2/2/2027 is actually their goal, your EDATE formula would be my recommendation too.
 
Upvote 0
Hi guys, thank you all for your replies, amazing! I will post my formula, an an extract from the lookup table tomorrow when I get home.
 
Upvote 0

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