Loop To count a consecutive series

mthpsu

New Member
Joined
Jun 23, 2011
Messages
3
Hi All,

I'm a bit of a newbie at this, so pardon this possibly basic question. I have a 370,000 or so line spreadsheet, containing one column of only 1's and 0's. I need to find all of the instances in which I have 50 (or more) repeating 1's in a row. I know this should be able to be done with a simple loop, but I'm getting nowhere. Any help?
 

Excel Facts

Which Excel functions can ignore hidden rows?
The SUBTOTAL and AGGREGATE functions ignore hidden rows. AGGREGATE can also exclude error cells and more.
Try this:-
Code:
[COLOR="Navy"]Sub[/COLOR] MG24Jun48
[COLOR="Navy"]Dim[/COLOR] Rng [COLOR="Navy"]As[/COLOR] Range, Dn [COLOR="Navy"]As[/COLOR] Range, n [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]Long[/COLOR]
[COLOR="Navy"]Dim[/COLOR] nRng [COLOR="Navy"]As[/COLOR] Range
[COLOR="Navy"]Dim[/COLOR] R [COLOR="Navy"]As[/COLOR] Range
[COLOR="Navy"]Dim[/COLOR] msg [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]String[/COLOR]
[COLOR="Navy"]Set[/COLOR] Rng = Range(Range("A1"), Range("A" & rows.Count).End(xlUp))
[COLOR="Navy"]For[/COLOR] [COLOR="Navy"]Each[/COLOR] Dn [COLOR="Navy"]In[/COLOR] Rng
    [COLOR="Navy"]If[/COLOR] Dn = "1" [COLOR="Navy"]Then[/COLOR]
        [COLOR="Navy"]If[/COLOR] nRng [COLOR="Navy"]Is[/COLOR] Nothing [COLOR="Navy"]Then[/COLOR]
            [COLOR="Navy"]Set[/COLOR] nRng = Dn
        [COLOR="Navy"]Else[/COLOR]
            [COLOR="Navy"]Set[/COLOR] nRng = Union(nRng, Dn)
        [COLOR="Navy"]End[/COLOR] If
    [COLOR="Navy"]End[/COLOR] If
[COLOR="Navy"]Next[/COLOR] Dn
[COLOR="Navy"]For[/COLOR] [COLOR="Navy"]Each[/COLOR] R [COLOR="Navy"]In[/COLOR] nRng.Areas
    [COLOR="Navy"]If[/COLOR] R.Count >= 10 [COLOR="Navy"]Then[/COLOR]
        msg = msg & R.Address & chr(10)
    [COLOR="Navy"]End[/COLOR] If
[COLOR="Navy"]Next[/COLOR] R
MsgBox "Ranges of count 50 or greater " & chr(10) & msg
[COLOR="Navy"]End[/COLOR] [COLOR="Navy"]Sub[/COLOR]
Regards Mick
 
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