Percentage completed in column F

xeven_

Active Member
Joined
Jan 20, 2012
Messages
302
My spreadsheet has #'s 1-67 in column A. I want to put a formula in column F that will calculate the percentage of each row to 100%. What is the formula I can use?

[TABLE="width: 578"]
<colgroup><col><col span="2"><col><col><col></colgroup><tbody>[TR]
[TD]1[/TD]
[TD]Homework Orientation[/TD]
[TD] [/TD]
[TD] %[/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
[TR]
[TD]2[/TD]
[TD]Homework 1.1 Standard Notation[/TD]
[TD] [/TD]
[TD]
%

[/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
[TR]
[TD]3[/TD]
[TD]Homework 1.2 Addition[/TD]
[TD] [/TD]
[TD] %[/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]Homework 1.3 Subtraction[/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]Homework 1.4 Multiplication[/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
[TR]
[TD]6[/TD]
[TD]Homework 1.5 Division[/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
[TR]
[TD]7[/TD]
[TD]Homework 1.6 Rounding, Estimating, and Order[/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
[TR]
[TD]8[/TD]
[TD]Homework 1.7 Solving Equations[/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
[TR]
[TD]9[/TD]
[TD]Homework 1.8 Applications & Prob Solving[/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[TD] [/TD]
[/TR]
</tbody>[/TABLE]
 

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The percentage of that row from all of the rows used. In this case I have 67 rows filed in and the 67th row will represent 100%. So I want a formula that will calculate the preceding rows eg: 67 is 100%, 66 will be ?%. 65 ?%....
 
Upvote 0
Is this what you mean? If not, more details please.

Formula in F2 copied down to the end of the numbers in column A.

Note that I've hidden most of my rows to keep the screen shot small.

Excel Workbook
ABCDEF
1Num%
211.49%
322.99%
434.48%
545.97%
657.46%
768.96%
8710.45%
9811.94%
626191.04%
636292.54%
646394.03%
656495.52%
666597.01%
676698.51%
6867100.00%
69
Percentage
 
Upvote 0
Oh You are AWESOME!!!!
I wish you taught college classes on Excel only!
I love Australia always wanted to move there!

Thanks again Peter. :)
 
Upvote 0

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