Retrive the maximum value of a row, only if the entire row is filled with values. Can this be done without vba?

mcva

New Member
Joined
Apr 20, 2020
Messages
28
Office Version
  1. 365
Platform
  1. Windows
Hello, I have several sheets with this kind of format (7000 rows)
The output I need is the maximum value in each row. But I only want to retrive the value if the corresponding row is filled with values ...
Can this be done without vba?
Thank you.

Test.jpg
 
What about
=IF(B2="","",IFERROR(INDEX(A2:G2,AGGREGATE(14,6,COLUMN(A2:H2)/(COLUMN(A2:H2)<AGGREGATE(15,6,COLUMN(A2:H2)/((A2:H2)=""),1)),1)),""))

Book1
ABCDEFGHI
1
202,74,74,7
30 
402,74,710,74,7
506,78,710,7 
602,74,74,7
702,74,76,78,78,7
806,78,710,7 
94,76,78,710,712,7 
1002,74,76,78,710,712,712,7
Sheet1
Cell Formulas
RangeFormula
I2:I10I2=IF(B2="","",IFERROR(INDEX(A2:G2,AGGREGATE(14,6,COLUMN(A2:H2)/(COLUMN(A2:H2)<AGGREGATE(15,6,COLUMN(A2:H2)/((A2:H2)=""),1)),1)),""))
 
Upvote 0

Excel Facts

What is =ROMAN(40) in Excel?
The Roman numeral for 40 is XL. Bill "MrExcel" Jelen's 40th book was called MrExcel XL.
What about
=IF(B2="","",IFERROR(INDEX(A2:G2,AGGREGATE(14,6,COLUMN(A2:H2)/(COLUMN(A2:H2)<AGGREGATE(15,6,COLUMN(A2:H2)/((A2:H2)=""),1)),1)),""))

Book1
ABCDEFGHI
1
202,74,74,7
30 
402,74,710,74,7
506,78,710,7 
602,74,74,7
702,74,76,78,78,7
806,78,710,7 
94,76,78,710,712,7 
1002,74,76,78,710,712,712,7
Sheet1
Cell Formulas
RangeFormula
I2:I10I2=IF(B2="","",IFERROR(INDEX(A2:G2,AGGREGATE(14,6,COLUMN(A2:H2)/(COLUMN(A2:H2)<AGGREGATE(15,6,COLUMN(A2:H2)/((A2:H2)=""),1)),1)),""))
What about
=IF(B2="","",IFERROR(INDEX(A2:G2,AGGREGATE(14,6,COLUMN(A2:H2)/(COLUMN(A2:H2)<AGGREGATE(15,6,COLUMN(A2:H2)/((A2:H2)=""),1)),1)),""))

Book1
ABCDEFGHI
1
202,74,74,7
30 
402,74,710,74,7
506,78,710,7 
602,74,74,7
702,74,76,78,78,7
806,78,710,7 
94,76,78,710,712,7 
1002,74,76,78,710,712,712,7
Sheet1
Cell Formulas
RangeFormula
I2:I10I2=IF(B2="","",IFERROR(INDEX(A2:G2,AGGREGATE(14,6,COLUMN(A2:H2)/(COLUMN(A2:H2)<AGGREGATE(15,6,COLUMN(A2:H2)/((A2:H2)=""),1)),1)),""))

It works thank you so much
 
Upvote 0
yes they are
Thanks. Then depending on your exact circumstances, you could also try any of these.

20 04 22.xlsm
ABCDEFGHIJK
1
202.74.74.74.74.7
30   
402.74.710.74.74.74.7
506.78.710.7   
602.74.74.74.74.7
702.74.76.78.78.78.78.7
806.78.710.7   
94.76.78.710.712.7   
1002.74.76.78.710.712.712.712.712.7
Sheet2 (3)
Cell Formulas
RangeFormula
I2:I10I2=IF(COUNT(A2:B2)=2,INDEX(A2:G2,MATCH(1,(B2:H2="")*(A2:G2<>""),0)),"")
J2:J10J2=IF(COUNT(A2:B2)=2,INDEX(FILTER(B2:F2,(B2:F2<>"")*(C2:G2=""),G2),1),"")
K2:K10K2=IF(COUNT(A2:B2)=2,IF(COUNTBLANK(A2:G2),MINIFS(B2:G2,B2:G2,"<>",C2:H2,""),G2),"")
 
Upvote 0

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