second to last in row

taino8632

Board Regular
Joined
Nov 16, 2004
Messages
90
I am using the following formula to determine the second to last numeric value in a row.

=LOOKUP(2^15,$C2:INDEX($C2:$BB2,MATCH(2^15,$C2:$BB2)-1))

However, in cases where there is only one value in the row I am getting an #N/A error. How do I account for this error? I want to return a blank if there is only one value in the row.

Thanks for your help.
 

Excel Facts

Why are there 1,048,576 rows in Excel?
The Excel team increased the size of the grid in 2007. There are 2^20 rows and 2^14 columns for a total of 17 billion cells.

lenze

Legend
Joined
Feb 18, 2002
Messages
13,690
Code:
IF(COUNT($C2:$BB2)=1,"",LOOKUP(2^15,$C2:INDEX($C2:$BB2,MATCH(2^15,$C2:$BB2)-1))
lenze
 

jasonb75

Well-known Member
Joined
Dec 30, 2008
Messages
12,959
Office Version
  1. 365
Platform
  1. Windows
In excel 07 or 10

=IFERROR(LOOKUP(2^15,$C2:INDEX($C2:$BB2,MATCH(2^15,$C2:$BB2)-1)),"")

In 03 or older

=IF(ISNA(LOOKUP(2^15,$C2:INDEX($C2:$BB2,MATCH(2^15,$C2:$BB2)-1))),"",LOOKUP(2^15,$C2:INDEX($C2:$BB2,MATCH(2^15,$C2:$BB2)-1)))
 

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