sunwordelite
New Member
- Joined
- Sep 7, 2009
- Messages
- 15
=CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));1))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));2))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));3))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));4))
CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1))
Sir using Excel 2013@sunwordelite
What version of Excel are you using?
Please update your account details to show this, as it affects what functions you can use.
Cell Formulas | ||
---|---|---|
Range | Formula | |
C10:C12 | C10 | =TEXT(SUM(SMALL(--MID(B10,ROW(INDIRECT("1:"&LEN(B10))),1),ROW(INDIRECT("1:"&LEN(B10))))*10^(LEN(B10)-ROW(INDIRECT("1:"&LEN(B10))))),REPT("0",LEN(B10))) |
Press CTRL+SHIFT+ENTER to enter array formulas. |
Sir I copy this formula got errorA formula like
Excel Formula:=CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));1))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));2))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));3))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));4))
should do it for a 4-digit number. I dunno if there is any way to generalize it for an arbitrary amount of digits.
View attachment 27516
As you see it is the formula
Excel Formula:CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1))
concatenated several times. You need to have as many digits inside the curly braces as there are digits in the number, and you need to increase the last argument in the function by one for every concatenation.
I found the formula here.
Sir I try first thanks for replyOk, how about
Cell Formulas Range Formula C10:C12 C10 =TEXT(SUM(SMALL(--MID(B10,ROW(INDIRECT("1:"&LEN(B10))),1),ROW(INDIRECT("1:"&LEN(B10))))*10^(LEN(B10)-ROW(INDIRECT("1:"&LEN(B10))))),REPT("0",LEN(B10))) Press CTRL+SHIFT+ENTER to enter array formulas.
Please don't forget to update your account details & then scroll down & click Save.
sir thank you very much formula work well for 3dA formula like
Excel Formula:=CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));1))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));2))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));3))&CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1));4))
should do it for a 4-digit number. I dunno if there is any way to generalize it for an arbitrary amount of digits.
View attachment 27516
As you see it is the formula
Excel Formula:CHAR(SMALL(CODE(MID(B3;{1;2;3;4};1))
concatenated several times. You need to have as many digits inside the curly braces as there are digits in the number, and you need to increase the last argument in the function by one for every concatenation.
I found the formula here.
sir sorry late reply.i try to copy the formula not workWait si
Sir I try first thanks for reply