staff schedule

imported_unknown

Active Member
Joined
Jan 13, 2002
Messages
424
I am trying to create a staff schedule. It will finally figure the hours between start and end time, and subtract .5 hour for lunch. Now I need to add another condition for those working less than 5 hours. These should not have the .5 subtracted. This is how I was doing it so far.
=IF((24*(IF(C8>D8,D8+1-C8,D8-C8))-0.5)>0,(24*(IF(C8>D8,C8+1-C8,D8-C8))-0.5),0)
Help?
Thanks.
 

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flexinau

Board Regular
Joined
Sep 22, 2002
Messages
122
This formula will not work for difference in start and end times of 24 hours or more as the formula does not know the days worked.
Formula should work since no staff will work 24 hours straight.
For work of greater than 5 hours, the formula will take .5 hours for break. 5 hours or less, no 0.5 hours for breaks are deducted.

=IF((24*(IF(C8>D8,D8+1-C8,D8-C8))-0.5)>5,(24*(IF(C8>D8,D8+1-C8,D8-C8))-0.5),24*(D8-C8))
 

Yogi Anand

MrExcel MVP
Joined
Mar 12, 2002
Messages
11,454
On 2002-10-04 23:07, GLD wrote:
I am trying to create a staff schedule. It will finally figure the hours between start and end time, and subtract .5 hour for lunch. Now I need to add another condition for those working less than 5 hours. These should not have the .5 subtracted. This is how I was doing it so far.
=IF((24*(IF(C8>D8,D8+1-C8,D8-C8))-0.5)>0,(24*(IF(C8>D8,C8+1-C8,D8-C8))-0.5),0)
Help?
Thanks.

Hi GLD:

Welcome to the Board!

Try ...

=IF(((D8-C8)+(C8>D8))*24>5,((D8-C8)+(C8>D8))*24-0.5,((D8-C8)+(C8>D8))*24)

Regards!

Yogi
 

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