VBA code running slow after specific code was executed

Roy_Excel_Island_Apps

Board Regular
Joined
Oct 9, 2018
Messages
76
Office Version
  1. 365
Platform
  1. Windows
Hi guys,

something weird is happening in my workbook code. I've been searching for hours what was slowing down the process:

1. I run my code when I've opened the workbook: 0 seconds to execute it.
2. I run my code a second time: Going 1 record per second (And I have 10K records...), so VERY SLOW
3. While running I break the execution and click 'End' so the macro stops.
4. I run it again: 0 seconds!
5. Step 2 happens again...
6. Loop..

I had a look at what is causing the code going slow at the second time you run it and this is the code:

' Set rng = shtOUTPUT.Range("A2:A" & LR)
' shtOUTPUT_Template.Range("H2").Resize(rng.Rows.Count, rng.Columns.Count).Cells.Value = rng.Cells.Value
'
' Set rng = shtOUTPUT.Range("B1:BE" & LR)
' shtOUTPUT_Template.Range("N1").Resize(rng.Rows.Count, rng.Columns.Count).Cells.Value = rng.Cells.Value

' Set rng = Nothing

When I put the code above in comments, the code is running FAST EVERY EXECUTION. So I am sure this code is slowing it down...BUT I DON'T KNOW WHY...
Can somebody tell me why??? Thanks in advance!

Regards, Roy
 

Excel Facts

Which came first: VisiCalc or Lotus 1-2-3?
Dan Bricklin and Bob Frankston debuted VisiCalc in 1979 as a Visible Calculator. Lotus 1-2-3 debuted in the early 1980's, from Mitch Kapor.
Does the value of LR change between the fast & slow runs?
 
Upvote 0
Does the value of LR change between the fast & slow runs?

LR = shtOUTPUT.Cells(shtOUTPUT.Rows.Count, "A").End(xlUp).Row

So yes. It counts the last row. This is always the same because I clear the sheet in the beginning of the execution: 'shtOUTPUT.Rows("2:" & Rows.Count).ClearContents'
 
Upvote 0

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