Yet more nest IF and AND

[jomcgowan]

I'd like to check whether the value of each of three cells is zero or more than zero and return a result for the 7 logical posibilities.

I *think* I might need a nested IF statement but I am at a complete loss as to where to start.

Any help appreciated - both in the formula but also the understanding why that's what I need so maybe I get closer myself next time... thank you

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BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; HEIGHT: 12.75pt; BACKGROUND-COLOR: transparent" height=17>centre 1</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent">a only</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; HEIGHT: 12.75pt; BACKGROUND-COLOR: transparent" height=17>centre 2</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent">a and b</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; HEIGHT: 12.75pt; BACKGROUND-COLOR: transparent" height=17>centre 3</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent">a and c</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; HEIGHT: 12.75pt; BACKGROUND-COLOR: transparent" height=17>centre 4</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent">a,b and c</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; HEIGHT: 12.75pt; BACKGROUND-COLOR: transparent" height=17>centre 5</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent">b only</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; HEIGHT: 12.75pt; BACKGROUND-COLOR: transparent" height=17>centre 6</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent; mso-ignore: colspan" colSpan=2>b and c only</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD></TR><TR style="HEIGHT: 12.75pt" height=17><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; HEIGHT: 12.75pt; BACKGROUND-COLOR: transparent" height=17>centre 7</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent">c only</TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD><TD class=xl24 style="BORDER-RIGHT: #e0dfe3; BORDER-TOP: #e0dfe3; BORDER-LEFT: #e0dfe3; BORDER-BOTTOM: #e0dfe3; BACKGROUND-COLOR: transparent"></TD></TR></TBODY></TABLE>

 

[Jonmo1]

If 1 and 0 are the only options, the perhaps..

=LOOKUP((A1&B1&C1)*1,{1,"c only";10,"b only";11,"b and c only";100,"a only";101,"a and c";110,"a and b";111,"a,b and c"})

 

[jomcgowan]

Thanks for the quick reply - the values in the cells may be more than 1 though, so 1 and 0 aren't the only options.

 

[Jonmo1]

So it's either 0 or not zero?

 

[Jonmo1]

this will be either 0 or Greater Than 0 (not negative)

=LOOKUP((--(A1>0)&--(B1>0)&--(C1>0))*1,{1,"c only";10,"b only";11,"b and c only";100,"a only";101,"a and c";110,"a and b";111,"a,b and c"})

 

[jomcgowan]

Hello, that's brilliant, thank you. It works perfectly.
I've no idea what it is doing though.

I'd be ever so grateful if you have a chance to explain.

 

[Jonmo1]

Perhaps breaking it into pieces will help.
Using the original assumption of 1 or 0 the only options (explain more after).

Excel Workbook
	A	B	C	D	E	F	G	H	I	J	K
1	A	B	C		Concatenate	Multiply X 1		Lookup		Lookup Table
2	1	0	0		100	100		a only		1	c only
3	1	1	0		110	110		a and b		10	b only
4	1	0	1		101	101		a and c		11	b and c only
5	1	1	1		111	111		a,b and c		100	a only
6	0	1	0		010	10		b only		101	a and c
7	0	1	1		011	11		b and c only		110	a and b
8	0	0	1		001	1		c only		111	a,b and c
Sheet1

 

[Jonmo1]

The only difference between post #2 and post #5 is

Post 2
(A1&B1&C1)*1

Post 5
((--(A1>0)&--(B1>0)&--(C1>0))*1

Each of the parts uses -- to convert the question (A1>0) from True/False to either 1 or 0
0's stay 0's, anything >0 converts to 1