Count with interval conditional

ibmy

Board Regular
Joined
Mar 4, 2020
Messages
115
Office Version
  1. 2016
Platform
  1. Windows
Column A / Column B // Column C

0 / 0.1 // (1)
0 / -0.1 // (2)
0 / 0.1 // (3)
0 / -0.1 // (4)
0 / 0.1 // (5)
-0.1 / 0 // (1)
0.1 / 0 // (2)
0.1 / 0 // (1)
0.7 / 0 //
-0.1 / 0.5 //


Rule:
1) Starting value is 0.1 or -0.1
> Exist at column A or B
2) Other column must 0
3) The count start if next row is -0.1 (starting 0.1) and 0.1 (starting from -0.1).
> The count continues 0.1 -> -0.1 -> 0.1 ........ as long as its not break all above rule..

Break of Rule:
1) Break if other column is not 0
2) Break if it not follow by 0.1 / -0.1

Example of break rule:

1) The count reset (not continue) when not follow 0.1 -> -0.1 -> 0.1 ......

-0.1/ 0 // (1)
0.1 / 0 // (2)
0.1 / 0 // (1)
0.1 / 0 // (1)
0 / -0.1 // (1)
0 / -0.1 // (1)

2) No count when follow by other number than 0.1 / -0.1

-0.1/ 0 // (1)
0.1 / 0 // (2)
0.7 / 0 //

3) No count when other column is not 0.

-0.1 / 0 // (1)
0.1 / 0 // (2)
-0.1 / 0.5 //

p/s:
If 2 column (A&B) is hard to formula at the same time, then formula for 1 column will do. I can do 1 column at one time. I test column A first then column B ( I will apply formula to count at column A first then column B).

Thanks.
 

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Formula for Yesterday
Name Manager, New Name. Yesterday =TODAY()-1. OK. Then, use =YESTERDAY in any cell. Tomorrow could be =TODAY()+1.
I suspect that there's a shorter formula, but I got tied up in knots trying to find one. So I just went back to basics and came up with:


Book1
ABC
1Column AColumn BColumn C
200.11
30-0.12
400.13
50-0.14
600.15
7-0.101
80.102
90.101
100.70 
11-0.10.5 
120.101
13-0.102
140.103
15-0.12 
160.101
170.101
180.101
19-0.102
2000.11
210-0.12
220-0.11
Sheet20
Cell Formulas
RangeFormula
C2:C22C2=IF(AND(A2=0,A1=0,B2=0.1,B1=-0.1),N(C1)+1,IF(AND(A2=0,A1=0,B2=-0.1,B1=0.1),N(C1)+1,IF(AND(A2=0.1,A1=-0.1,B2=0,B1=0),N(C1)+1,IF(AND(A2=-0.1,A1=0.1,B2=0,B1=0),N(C1)+1,IF(AND(COUNTIF(A2:B2,0)=1,ABS(A2+B2)=0.1),1,"")))))
 
Upvote 0
Solution

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