Excel 2003 COUNTIF using 2 parameters

tomshaw4

New Member
Joined
Apr 17, 2013
Messages
23
Hello

I am trying to get a the number of cells that have a value of 1 in each column from the following table

SR</SPAN>Email in</SPAN>Email Out</SPAN>
1-100000042-7</SPAN>1</SPAN>1</SPAN>
1-105414900-7</SPAN>1</SPAN>1</SPAN>
1-109295564-7</SPAN>1</SPAN>1</SPAN>
1-112045199-7</SPAN>1</SPAN>1</SPAN>
1-120700322-7</SPAN>1</SPAN>1</SPAN>
1-125862229-7</SPAN>1</SPAN>1</SPAN>
1-125970213-7</SPAN>1</SPAN>1</SPAN>
1-125998569-7</SPAN>1</SPAN>1</SPAN>
1-126474609-7</SPAN>1</SPAN>1</SPAN>
1-126768968-7</SPAN>1</SPAN>1</SPAN>

<TBODY>
</TBODY><COLGROUP><COL><COL span=2></COLGROUP>

I have tried using the following formula

COUNTIF((B1:B10,"=1") and (C1:C10,"=1"))

But it is not working. Can you advise what I am doing wrong.
 

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tomshaw4

New Member
Joined
Apr 17, 2013
Messages
23
Thanks for the update Peter.

I have added this to the workbook and it delivers an value of 0. I have also used the Ctrl, shift and enter option and still comes back with 0.

I was expecting a result of 10. Am I doing anything wrong? Any other ideas?

Regards
 

VoG

Legend
Joined
Jun 19, 2002
Messages
63,650
Working here

Excel Workbook
ABC
1SRInOut
21-100000042-711
31-105414900-711
41-109295564-711
51-112045199-711
61-120700322-711
71-125862229-711
81-125970213-711
91-125998569-711
101-126474609-711
111-126768968-711
Sheet1




What does

=ISNUMBER(B2)

return?
 

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