kumara_faith
Well-known Member
- Joined
- Aug 19, 2006
- Messages
- 880
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Hi,
I have a list of employee numbers in the following format:
770205145598
The first two numbers are the year, second two digits are the month and the next two digits are the day. So, in this case the employees' date of birth is February 5 1977. Is there a way to extract the date of birth in mm/dd/yyyy format ? Thank you in advance.
I have a list of employee numbers in the following format:
770205145598
The first two numbers are the year, second two digits are the month and the next two digits are the day. So, in this case the employees' date of birth is February 5 1977. Is there a way to extract the date of birth in mm/dd/yyyy format ? Thank you in advance.