Find two consecutive rows that begin with same letter, delete the top one.

User45

New Member
Joined
Jun 28, 2013
Messages
25
Hello,
I have "A" column . A1 cell begins with letter "S". A2 begins with "K". A3 begins with "S" again.A4 begins with "K" again.
Code:
S...
K...
S...
K...
S...
K...

e.t.c

The problem is, sometimes there will be rows like
Code:
S...
Ky...
Kz...
St...
Sp...
K...

If you noticed the 2nd and 3rd one both begin with "K", while 4th and 5th both begin with "S".I'm looking for a spreadsheet formula that would delete the top one ,out of two consecutive rows with the same letter, so the final would be
Code:
S...
Kz...
Sp...
K...

Every cell has bunch of data in it but they always begin either with "S" or "K".
Not sure if I should open another post but my next step would be moving the "K" cells to "B" colum to make it look like
A B
----
S K
S K
S K
S K
my main problem is the first question, however.

I'm totally fine even if I have to go through a dozen steps, as long as it's a formula.Any help is appreciated.Thanks !
 

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Domenic

MrExcel MVP
Joined
Mar 10, 2004
Messages
19,406
Let's assume that A2:A7 contains the data, try...

C1, confirmed with CONTROL+SHIFT+ENTER:

=SUM(IF(FREQUENCY(IF(LEFT(A2:A7,1)="S",ROW(A2:A7)),IF(LEFT(A2:A7,1)<>"S",ROW(A2:A7)))>0,1))

D1, confirmed with CONTROL+SHIFT+ENTER:

=SUM(IF(FREQUENCY(IF(LEFT(A2:A7,1)="K",ROW(A2:A7)),IF(LEFT(A2:A7,1)<>"K",ROW(A2:A7)))>0,1))

C2, confirmed with CONTROL+SHIFT+ENTER, and copied down:

=IF(ROWS(C$2:C2)<=C$1,INDEX($A$2:$A$7,SMALL(IF(LEFT($A$3:$A$8,1)<>"S",IF(LEFT($A$2:$A$7,1)="S",ROW($A$2:$A$7)-ROW($A$2)+1)),ROWS(C$2:C2))),"")

D2, confirmed with CONTROL+SHIFT+ENTER, and copied down:

=IF(ROWS(D$2:D2)<=D$1,INDEX($A$2:$A$7,SMALL(IF(LEFT($A$3:$A$8,1)<>"K",IF(LEFT($A$2:$A$7,1)="K",ROW($A$2:$A$7)-ROW($A$2)+1)),ROWS(D$2:D2))),"")

Notice that within the SMALL functions, the first range reference is offset from the second range reference by one cell.

Hope this helps!
 

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