How do I use the range property using variables

andyjames

Board Regular
Joined
May 15, 2007
Messages
133
At the moment I have the following code

Range("F7:H13").Select
With Selection.Interior
.ColorIndex = 44
.Pattern = xlSolid
End With


How do I replace this so that the F, 7, H and 13 are all variables that can change in the program?
 

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Norie

Well-known Member
Joined
Apr 28, 2004
Messages
76,218
Office Version
  1. 365
Platform
  1. Windows
Well that really depends on your variables.

Could be something like this.
Code:
With Range("F" & FirstRow & ":H" & LastRow)
     .ColorIndex = 44
     .Pattern = xlSolid
End With
 

andyjames

Board Regular
Joined
May 15, 2007
Messages
133
Thanks.
Unfortunately this also involves knowing the columns (namely, F and H).
May be it's not the RANGE property I should be using.
But I wanted my programme to be able to change (increment) the columns also.
Any ideas?
 

Norie

Well-known Member
Joined
Apr 28, 2004
Messages
76,218
Office Version
  1. 365
Platform
  1. Windows
Well it's hard to say without seeing the rest of the code, the variables and more information on what you want to achieve.:)

Some ideas though - Cells, Resize, Offset.
 

markadon

Board Regular
Joined
Feb 12, 2007
Messages
193
The following code, placed in a module by itself, will do the trick. You pass in the column numbers and row numbers. You can easily adapt this to take the columns as letters ("F"-"H") rather than numbers (6'8).

THANKS TO RICHARDSCHOLLAR

Option Explicit

Sub test()
ColorCells 6, 7, 8, 13
End Sub

Function ColLet(piNum As Integer) As String
ColLet = Split(Cells(1, piNum).Address(, False), "$")(0)
End Function

Sub ColorCells(piStartCol As Integer, piStartRow As Long, _
piStopCol As Integer, piStopRow As Long)
Dim sStartLet As String
Dim sStopLet As String
sStartLet = ColLet(piStartCol)
sStopLet = ColLet(piStopCol)
Range(sStartLet & piStartRow & ":" & sStopLet & piStopRow).Select
Selection.Interior.ColorIndex = 44
Selection.Interior.Pattern = xlSolid
End Sub


--Doug
 

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