index Match with drop down

dsami0122

New Member
Joined
Mar 31, 2016
Messages
13
Office Version
  1. 365
Platform
  1. Windows
I have a file I am using a drop down list for a classification. What I want to be able to do is dependant on what is selected from the drop down it populates from a list of data. So if I select Admin it will return all the names of the admins from the data file.
 

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AhoyNC

Well-known Member
Joined
Oct 10, 2011
Messages
4,840
Office Version
  1. 365
Platform
  1. Windows
If you have Excel 2010 or later try the formula in D3 and drag down the column as needed.
If you have Excel 365 then the formula in F3.
Change data to match your data.

Book2
ABCDEF
1NameListAdmin
2Name1Admin
3Name2Cust. ServiceName1Name1
4Name3AdminName3Name3
5Name4SalesName7Name7
6Name5Mgr 
7Name6Mgr 
8Name7Admin 
9Name8Sales
Sheet1
Cell Formulas
RangeFormula
F3:F5F3=FILTER($A$2:$A$9,$B$2:$B$9=$E$1,"")
D3:D8D3=IFERROR(INDEX($A$2:$A$9,AGGREGATE(15,6,(ROW($A$2:$A$9)-ROW($A$2)+1)/($B$2:$B$9=$E$1),ROWS($E$3:E3))),"")
Dynamic array formulas.
 

AhoyNC

Well-known Member
Joined
Oct 10, 2011
Messages
4,840
Office Version
  1. 365
Platform
  1. Windows
You're welcome. Thanks for the feedback. You may want to add the version of Excel you are using to your account info.
 

dsami0122

New Member
Joined
Mar 31, 2016
Messages
13
Office Version
  1. 365
Platform
  1. Windows
One question Im using this formula
D3:D8D3=IFERROR(INDEX($A$2:$A$9,AGGREGATE(15,6,(ROW($A$2:$A$9)-ROW($A$2)+1)/($B$2:$B$9=$E$1),ROWS($E$3:E3))),"")

What does this do ROWS($E$3:E3))),"") at the end I want to make sure I am grabbing the right data
 

AhoyNC

Well-known Member
Joined
Oct 10, 2011
Messages
4,840
Office Version
  1. 365
Platform
  1. Windows
The AGGREGATE function use the SMALL function to find each of the rows that match the data from your drop down. The ROWS($E$3:E3) returns 1,2,3 etc. as the formula is dragged down. So, the formula finds the 1st match then second match etc. to return the multiple names.
In the example above
(ROW($A$2:$A$9)-ROW($A$2)+1)/($B$2:$B$9=$E$1)
returns
{1;#DIV/0!;3;#DIV/0!;#DIV/0!;#DIV/0!;7;#DIV/0!} - so rows 1,3 and 7 match the rows with Admin.

The formula then returns rows 1,3 and 7 to the INDEX function.
 

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