PaulGladis
New Member
- Joined
- Apr 26, 2011
- Messages
- 2
Hello all!
I would like to know if anyone help me with a formula that tests a word to see if it's an isogram - a word that has no repeating letters.
I've set up a 26 column test searching the word letter by letter and checking for the number of occurences of each of the 26 letters in the alphabet. This works fine for the English alphabet, but I've got some German, Polish, Czech and words from many other languages in the list that use characters that are not found in our alphabet.
Before I go plugging in more test columns for these characters (ñ, ç,[FONT="] ä, ģ, Š, ǽ, etc), is there a way I can test for isograms with one single formula? And is it possible to make it NOT case sensitive - i.e. it counts 'c' and 'C' as two occurences and not one of each. Or should i just use the '=lower()' forumla to format the words beforehand?
I appreciate your expertise and hope there's some way we can accomplish this!
Thanks,
Paul
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I would like to know if anyone help me with a formula that tests a word to see if it's an isogram - a word that has no repeating letters.
I've set up a 26 column test searching the word letter by letter and checking for the number of occurences of each of the 26 letters in the alphabet. This works fine for the English alphabet, but I've got some German, Polish, Czech and words from many other languages in the list that use characters that are not found in our alphabet.
Before I go plugging in more test columns for these characters (ñ, ç,[FONT="] ä, ģ, Š, ǽ, etc), is there a way I can test for isograms with one single formula? And is it possible to make it NOT case sensitive - i.e. it counts 'c' and 'C' as two occurences and not one of each. Or should i just use the '=lower()' forumla to format the words beforehand?
I appreciate your expertise and hope there's some way we can accomplish this!
Thanks,
Paul
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