Left Function Variables for multiple cells in same column based on another column

J

jadess916

New Member
Joined
Jun 25, 2014
Messages
4
:ROFLMAO: Hi all,

So, I'd like to pull the first three digits from a different column and place them in another column while turning any other digits in the original column into zeros in the next column.

This is what I mean:

<colgroup><col><col></colgroup><tbody></tbody>

<tbody></tbody>

<colgroup><col><col><col></colgroup><tbody></tbody>
Column A
Column BColumn CColumn D
$123,456.78
 $123,000.00
$89,798.90
 $89,700.00
$3,894.03
 $3,890.00

<colgroup><col><col><col><col></colgroup><tbody>
</tbody>


I'm not sure this is even possible but I'm sure there's a way to get it to work that is way beyond me.
 

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Here's one way

=LEFT(A1,3)*10^(LEN(INT(A1))-3)

There's probably a quicker more logical solution
 
Upvote 0
Try this too:

Layout

$123.456,78$123.000,00
$89.798,90$89.700,00
$3.894,03$3.890,00
$123,56$123,00
$12,34$12,30
$1,23$1,23
$0,12$0,12
$0,01$0,01
**************************

<tbody>
</tbody>

Formula

Code: 
In B1

=INT(A1/LOOKUP(A1/100,10^(ROW(INDIRECT("1:20"))-5)))*LOOKUP(A1/100,10^(ROW(INDIRECT("1:20"))-5))

And copy down.

Markmzz
 
Upvote 0
Markmzz!!! OMGosh, thanks sooooooooo much! Virtual hugs! Thank you, thank you, thank you!!!! It works like a dream.:biggrin:

markmzz said:
Try this too:

Layout

$123.456,78$123.000,00
$89.798,90$89.700,00
$3.894,03$3.890,00
$123,56$123,00
$12,34$12,30
$1,23$1,23
$0,12$0,12
$0,01$0,01
**************************

<tbody>
</tbody>

Formula

Code: 
In B1

=INT(A1/LOOKUP(A1/100,10^(ROW(INDIRECT("1:20"))-5)))*LOOKUP(A1/100,10^(ROW(INDIRECT("1:20"))-5))

And copy down.

Markmzz
Click to expand...
 
Upvote 0
Just another one you can try:

<html><head><title>Excel Jeanie HTML</title></head><body>
Excel Workbook
AB
112,345,678.0012,300,000.00
21,234,567.80 1,230,000.00
3123,456.78 123,000.00
489,798.90 89,700.00
53,894.03 3,890.00
6123.56 123.00
710.23 10.20
81.22 1.22
90.12 0.12
100.01 0.01
Sheet1


</body></html>
 
Upvote 0
I'm late to this "party", but here is my offering...

=0+REPLACE(TEXT(A1,"0.000000000E+0"),5,7,"")

Format the cell as Currency.
 
Upvote 0
Try this too (a small modification in FormR's formula):

Code: 
=FLOOR(A1,10^(LEN(A1*100)-5))

Markmzz
 
Upvote 0
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