Hello,
I am trying to divide 11 people over two lines in 15 days (with group rotation possible every 3 days only). What I mean with 'equal' in this case is that every employee gets to work the same number of days (optimally) with any of the other employees. Below is an example of how this schedule looks like.
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</thead><tbody>
</tbody>
I thought by calculating the number of times that a specific combination of two employees would occur (by using COUNTIFS in a 11 by 11 matrix), I would be able to adjust the schedule manually by trial and error until the numbers in the matrix below would be as close together as I can get (only multiples of three possible). While trying to optimize the schedule I figured there might be a much easier way to optimize this schedule.
<colgroup><col><col><col><col><col></colgroup><thead>
</thead><tbody>
</tbody>
Help would be much appreciated
Excel 2010
Windows 7 enterprise
I am trying to divide 11 people over two lines in 15 days (with group rotation possible every 3 days only). What I mean with 'equal' in this case is that every employee gets to work the same number of days (optimally) with any of the other employees. Below is an example of how this schedule looks like.
A | B | C | |
---|---|---|---|
37 | Line | Line 2 | |
38 | Day 1 | ABCEH | DFGIJK |
39 | Day 2 | ABCEH | DFGIJK |
40 | Day 3 | ABCEH | DFGIJK |
41 | Day 4 | ACGHIK | BDEFJ |
42 | Day 5 | ACGHIK | BDEFJ |
43 | Day 6 | ACGHIK | BDEFJ |
44 | Day 7 | ABEGIJ | DCFHK |
45 | Day 8 | ABEGIJ | DCFHK |
46 | Day 9 | ABEGIJ | DCFHK |
47 | Day 10 | ACEIJK | BDFGH |
48 | Day 11 | ACEIJK | BDFGH |
49 | Day 12 | ACEIJK | BDFGH |
50 | Day 13 | ADFHJ | BCEGI |
51 | Day 14 | ADFHJ | BCEGI |
52 | Day 15 | ADFHJ | BCEGI |
<colgroup><col><col><col><col></colgroup><thead>
</thead><tbody>
</tbody>
Sheet1
I thought by calculating the number of times that a specific combination of two employees would occur (by using COUNTIFS in a 11 by 11 matrix), I would be able to adjust the schedule manually by trial and error until the numbers in the matrix below would be as close together as I can get (only multiples of three possible). While trying to optimize the schedule I figured there might be a much easier way to optimize this schedule.
J | K | L | M | |
---|---|---|---|---|
37 | A | B | C | |
38 | A | 6 | 9 | |
39 | B | 6 | 6 | |
40 | C | 9 | 6 |
<colgroup><col><col><col><col><col></colgroup><thead>
</thead><tbody>
</tbody>
Sheet1
Help would be much appreciated
Excel 2010
Windows 7 enterprise