Problems identifying row / column position

Mark.B

Board Regular
Joined
Jun 14, 2004
Messages
136
Hi there, I am using the follwing code to identify the row/column position of a particular value within a range of values (in this example, it is a value ranging from 1 to 10).

The probelm is however, If the 'Level' = 1, then the code below returns the row / column position for the value 10. Does anyone know what I am doing worng and how I can correct this.

Regards
Mark


Level = Range("A1").Value

With Worksheets(1).Range("B1:B10")
Set c = .Find(Level, LookIn:=xlValues)
If Not c Is Nothing Then
Level_Address = c.Address(RowAbsolute:=False)
Level_Row = c.Row
Level_Col_Num = c.Column
Level_Col_Let = Mid(c.Address, 2, (InStr(2, c.Address, "$")) - 2)
End If
End With
 

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erik.van.geit

MrExcel MVP
Joined
Feb 1, 2003
Messages
17,832
Hi,

the method "FIND" will always use the settings which were used before - be it manually or by VBA - therefore it's good practive to specify all relevant arguments

the "1" is part of "10" so your code probably looked to cell"parts"
so, add an argument "LOOKAT"
Code:
Set c = .Find(Level, LookIn:=xlValues, Lookat:=xlWhole)
take a look in the helpfiles about "FIND"

kind regards,
Erik
 

Zack Barresse

MrExcel MVP
Joined
Dec 9, 2003
Messages
10,881
Office Version
  1. 365
  2. 2010
Platform
  1. Windows
  2. Mobile
  3. Web
Try only looking at the Whole part of the cell value..

Code:
    Dim c As Range, ws As Worksheet
    Dim Level_Address As String, Level_Row As Long
    Dim Level_Col_Num As Long, Level_Col_Let As String
    Set ws = Worksheets(1)
    With ws.Range("B1:B10")
        Set c = .Find(what:=ws.Range("A1").Value, lookat:=xlWhole)
        If Not c Is Nothing Then
            Level_Address = c.Address(0)
            Level_Row = c.Row
            Level_Col_Num = c.Column
            Level_Col_Let = Left(ws.Cells(1, c.Column).Address(0, 0), Len(ws.Cells(1, c.Column).Address(0, 0)) - 1)
        End If
    End With
 

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