Replacing < and > with numbers using If Then loop

VAPALIPOT

New Member
Joined
Jan 18, 2010
Messages
14
I want to scan a column of numbers that occasionally contain some values that have either "< 0.000" or a "> 10" listed. When I find them, I need to write a slightly different string set to an adjacent column. I also need to write an integer to a third column as a FLAG. So when I find the "< 0.000", I need to replace it with a "<" and the cell value I have stored elsewhere (e.g., "N31"), then write a 5 to an adjacent cell on the same row. A similar activity occurs with the "> 10.4" except there is a multiplication that occurs to create the inserted value after the ">". Finally, an integer 2 is inserted into the same column as the 5.

Code:
Sub TEST1()
' This sub designed to screen for occurrences of "<" and ">" in Columns "6" and "8" respectively & insert appropriate answers in Column "8" and then insert corresponding flags in Col "9"
    Dim patternLESS As String
    Dim patternMORE As String
    Dim j As Integer    'j = row
    Dim I As Integer    'i = column
    Dim DilFactor As Long

    patternLESS = "<"
    patternMORE = ">"

    For j = 77 To 86
        If Cells(j, 6) = patternLESS Then
            Cells(j, 8) = "<" & "N31"
            Cells(j, 9) = 5
        End If
    Next j

    For j = 77 To 86
        If Cells(j, 6) = patternMORE Then
            DilFactor = Cell(j, 7).Value * Cell("N22").Value
            Cells(j, 8) = ">" & "DilFactor"
            Cells(j, 9) = 2
        End If
    Next j
End Sub

I tried to run this code but it came back with 'undefined function' at the DilFactor line where I was trying to multiply two cell values. My apologies as I couldn't find the section that indicated that I had code to upload on the Post New Thread section.

Thanks for your help.
 
Last edited by a moderator:
You are welcome!

Glad you got it working!
 
Upvote 0

Excel Facts

How to total the visible cells?
From the first blank cell below a filtered data set, press Alt+=. Instead of SUM, you will get SUBTOTAL(9,)

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