I have a strategy that I developed playing the table game roulette. I want to test it on large amounts of spins that I've previously recorded to see how it would have faired in the long term. I am hoping someone can understand my post and provide a formula that will help me.
Here goes:
There are 6 dozens of numbers. Let's call them Dozen 1, 2, 3, and A, B, C.
Dozen 1 are the numbers 1 through 12
Dozen 2 are the numbers 13 through 24
Dozen 3 are the numbers 25 through 36
Dozen A are the numbers 1,4,7,10,13,16,19,22,25,28,31 and 34
Dozen B are the numbers 2,5,8,11,14,17,20,23,26,29,32 and 35
Dozen C are the numbers 3,6,9,12,15,18,21,24,27,30,33 and 36
I need a formula that will record the numbers in 2 separate series of 6 in the following fashion:
Example: let's say the number 13 hits. So, every number has a numerical Dozen and an alphabetical number. For 13 it would be
2A (because it appears within Dozen 2 and Dozen A). But, I don't write it this way. The way it would be written is the 2 would be the start of the first series of 6 numbers and the B would be the start of the second series of 6 numbers.
So, it would be:
2
A
Let's say the next number is 26. So, that's a 3B, and it would go into the series as so:
2B
and
A3
The alpha-numeric numbers alternate in the series of 6.
So, if the next 4 numbers were 2,9,21 and 17: The 2 sets of 6 would look like this:
2B1C2B
and
A3B1C2
The next set of 6 would be placed in a grid directly under the first set of 6. So a comparison could be made between the number directly above. it would look like this:
First set of 6 with the second set of 6 (2nd set I just made up)
2B1C2B
1B2A2C
and
A3B1C2
C1B2C2
The numbers that are being used are in a single column. So, there would have to be a way to take those and place them in these 2 6 column grids and run continuously until all numbers in the column containing numbers were used.
I hope that I have explained this good enough for someone to understand.
I am very appreciative for any assistance you can provide.
Thanks very kindly.
JayZ
Here goes:
There are 6 dozens of numbers. Let's call them Dozen 1, 2, 3, and A, B, C.
Dozen 1 are the numbers 1 through 12
Dozen 2 are the numbers 13 through 24
Dozen 3 are the numbers 25 through 36
Dozen A are the numbers 1,4,7,10,13,16,19,22,25,28,31 and 34
Dozen B are the numbers 2,5,8,11,14,17,20,23,26,29,32 and 35
Dozen C are the numbers 3,6,9,12,15,18,21,24,27,30,33 and 36
I need a formula that will record the numbers in 2 separate series of 6 in the following fashion:
Example: let's say the number 13 hits. So, every number has a numerical Dozen and an alphabetical number. For 13 it would be
2A (because it appears within Dozen 2 and Dozen A). But, I don't write it this way. The way it would be written is the 2 would be the start of the first series of 6 numbers and the B would be the start of the second series of 6 numbers.
So, it would be:
2
A
Let's say the next number is 26. So, that's a 3B, and it would go into the series as so:
2B
and
A3
The alpha-numeric numbers alternate in the series of 6.
So, if the next 4 numbers were 2,9,21 and 17: The 2 sets of 6 would look like this:
2B1C2B
and
A3B1C2
The next set of 6 would be placed in a grid directly under the first set of 6. So a comparison could be made between the number directly above. it would look like this:
First set of 6 with the second set of 6 (2nd set I just made up)
2B1C2B
1B2A2C
and
A3B1C2
C1B2C2
The numbers that are being used are in a single column. So, there would have to be a way to take those and place them in these 2 6 column grids and run continuously until all numbers in the column containing numbers were used.
I hope that I have explained this good enough for someone to understand.
I am very appreciative for any assistance you can provide.
Thanks very kindly.
JayZ
