Sum Total Value of a Single Cell

JulianvO

New Member
Joined
Sep 9, 2022
Messages
27
Office Version
  1. 2021
Platform
  1. Windows
Greetings

Cell - A1 To contain formula

Cell - A2 To Display result of value entered into Cell A3

Cell - A3 Cell in which a numeric value is entered.

Formula must be-able to the sum total of the value entered into A3 and display the result in A2.

Example of Value entered into A3 1024 (No commas. spaces or plus signs. Just the number)

Sum total to be displayed in A2 must be 7 (1+0+2+4 = 7)

Example of Value entered into A3 123456789 (No commas. spaces or plus signs. Just the number)

Sum total to be displayed in A2 must be 45 (1+2+3+4+5+6+7+8+9=45)

Thanks
 

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How about
Fluff.xlsm
AB
1
210247
312345678945
Data
Cell Formulas
RangeFormula
B2:B3B2=SUM(MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1)+0)
 
Upvote 0
Here is another approach:
MrExcel_20220909.xlsx
A
1
245
3123456789
Sheet4
Cell Formulas
RangeFormula
A2A2=SUM(0+MID(A3,ROW($A$1:INDEX($A:$A,LEN(A3))),1))

Edit: I suppose it's more sensible to use the 0+ rather than 1* approach to coerce text to numbers...revised above.
 
Last edited:
Upvote 0
Hi, and another twist, if you have a sensible maximum number of digits that could be in the cell (I've used 15 in this example)

Book1
AB
1
210247
312345678945
Sheet1
Cell Formulas
RangeFormula
B2:B3B2=SUM(MID(A2&REPT(0,15),{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15},1)+0)
 
Upvote 0
Greetings Fjuff

Thanks for the speedy reply. I will try your solution.
 
Upvote 0
I would suggest using the formula from post#3 as it's not volatile
 
Upvote 0
Greetings

Thanks for the speedy reply. i will try your solution and see if it is what I require.
 
Upvote 0
Greetings

Thanks for the speedy reply. I will try your solution and see if it is what I need.
 
Upvote 0
Greetings

I have placed the formula into A1. I enter the following value 1024, into A3 and nothing happens.

What am I doing wrong?

Remember there is no text, commas, spaces or + signs, just the number.

The reason I need this is as follows:

Example:
Take number 1024. the sum total of this number 7 (1+0+2+4)
Now minus 7 from 1024 and you get 117. This remaining number is always divisible by 9. Answer is 13.
AS 9 is the square root of 3, the number will also be divisible by 3. Answer 39.

The above will apply to any number greater than 9. There will never be a remainder.
 
Upvote 0

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