Time Formula

Ark68

Well-known Member
Joined
Mar 23, 2004
Messages
4,564
Office Version
  1. 365
  2. 2016
Platform
  1. Windows
I need a little boost ...

Rich (BB code):
cmnshiftdur = Round((ecend - lcstart) * 24, 1)
tdiff = cmnshiftdur / 2

cmnshiftdur is the number of hours of overlap of two shifts
tdiff is half that value

I am failing in thought as to how to ...

Rich (BB code):
.Cells(DR, 2) = the value of ecend (end time of shift as a time value) - tiff formatted as "h:mm a/p" 


So if ecend = 3:00PM and tdiff = 1.5, the value in .Cells(DR, 2) = 1:30P
 

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I tried this,

Code:
.Cells(DR, 2) = format(DateAdd("m", tdiff, ecend), "h:mmA/P")
but am getting a result of 3:00PM.

Anyone?
 
Last edited:
Upvote 0
tdiff needs dividing by 24 if it is a decimal 1.5 as it would in the formula below


Excel 2010
ABC
23:00 PM13:30:00
31.5
Sheet1
Cell Formulas
RangeFormula
C2=A2-A3/24


and no need to use dateadd as it is a simple arithmetic sum
 
Last edited:
Upvote 0

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