Hi guys,
I would like to calculate the average power over a specified time range. I could use the average function. However, the time increments are not consistent. As you can see in the table, the time increments vary. I think that the average function would assume that each time row is equally spaced.
Is there a formula that I could use to calculate the power over a specific time range (e.g. 0.002383 - 0.008500 mins)? You can also see that a number of cells have #N/A and therefore the formula will need to ignore these cells.
Would a area under graph formula need to be used? If so, what formula would be required?
Below is a very small sample of my table:
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</tbody>
Thanks,
David
I would like to calculate the average power over a specified time range. I could use the average function. However, the time increments are not consistent. As you can see in the table, the time increments vary. I think that the average function would assume that each time row is equally spaced.
Is there a formula that I could use to calculate the power over a specific time range (e.g. 0.002383 - 0.008500 mins)? You can also see that a number of cells have #N/A and therefore the formula will need to ignore these cells.
Would a area under graph formula need to be used? If so, what formula would be required?
Below is a very small sample of my table:
Time | Engine Power |
(min) | (kW) |
0.000000 | #N/A |
0.000383 | 4.04 |
0.001017 | 4.12 |
0.001033 | #N/A |
0.001700 | #N/A |
0.001717 | #N/A |
0.002350 | #N/A |
0.002383 | 4.09 |
0.003067 | 4.09 |
0.003083 | #N/A |
0.003917 | #N/A |
0.003933 | #N/A |
0.004433 | 4.13 |
0.004967 | #N/A |
0.004983 | #N/A |
0.005517 | 4.06 |
0.005533 | #N/A |
0.005933 | #N/A |
0.005950 | #N/A |
0.006483 | 4.02 |
0.006967 | #N/A |
0.006983 | #N/A |
0.007433 | 4.09 |
0.007450 | #N/A |
0.007967 | 4.05 |
0.008500 | 4.09 |
0.008933 | #N/A |
0.008950 | #N/A |
0.009417 | #N/A |
0.009433 | #N/A |
0.009917 | 4.05 |
0.009933 | #N/A |
0.010550 | #N/A |
0.010567 | #N/A |
<colgroup><col><col><col><col></colgroup><tbody>
</tbody>
Thanks,
David