Extract the last characters in a cell.

quemuenchatocha

Board Regular
Joined
Aug 4, 2021
Messages
50
Office Version
  1. 365
  2. 2019
Platform
  1. Windows
Dear cordial greetings

I am learning the basics of Excel's VBA language, and I have come across the issue related to the default color range. Investigating in different sources I have found a code that allows to obtain the values for the RGB primary color palette, presenting them all together [Column C], or separately [Columns D:F] (the credits of the function correspond to Mr. Allen Wyatt, Determining the RGB Value of a Color).

Now, my question is directed to obtain the values recorded in column C, separately in columns H:J.

I have already obtained the respective values for column H (Color "R") and column I (Color "H"), through the implementation of combined functions, but I have found it difficult to obtain the last value for Color "B", which goes in column J.

Cell Formulas
RangeFormula
C2:C27C2=getRGB1(A2)
D2:D27D2=getRGB2(A2,1)
E2:E27E2=getRGB2(A2,2)
F2:F27F2=getRGB2(A2,3)
H2:H27H2=NUMBERVALUE(MID(LEFT(C2,FIND(",",C2)-1),FIND("(",C2)+1,LEN(C2)))
I2:I27I2=NUMBERVALUE(MID(C2,FIND(",",C2)+1,FIND(",",C2,FIND(",",C2)+1)-FIND(",",C2)-1))


I have tried various combinations with the functions RIGHT, MID, FIND, but have not obtained any satisfactory result. I apologize in advance for the length of the statement, and I appreciate any advice regarding how to obtain these last characters of the cell.

Thank you for your attention.

P.S.: In case the VBA functions are needed, here are the codes I use

VBA Code:
Sub ColorRef()

Dim x As Integer

For x = 1 To 56

If x <= 57 Then

ActiveCell(x, 1).Interior.ColorIndex = x

ActiveCell(x, 2) = x

End If

Next x

End Sub

VBA Code:
Function getRGB1(rcell) As String

Dim ColorVal As Long

Dim R As Long

Dim G As Long

Dim B As Long



ColorVal = rcell.Interior.Color

R = ColorVal Mod 256

G = ColorVal \ 256 Mod 256

B = ColorVal \ 65536 Mod 256

getRGB1 = "GRB(" & R & "," & G & "," & B & ")"

End Function

VBA Code:
Function getRGB2(rcell As Range, Optional opt As Integer) As Long

Dim ColorVal As Long

Dim R As Long

Dim G As Long

Dim B As Long



ColorVal = rcell.Interior.Color

R = ColorVal Mod 256

G = ColorVal \ 256 Mod 256

B = ColorVal \ 65536 Mod 256



If opt = 1 Then

getRGB2 = R

ElseIf opt = 2 Then

getRGB2 = G

ElseIf opt = 3 Then

getRGB2 = B

Else

getRGB2 = ColorVal

End If

End Function
 

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New__Document (11) (version 1).xlsb
ABCDEFG
2ColorColor IndexRGBRGB
31GRB(0,0,0)0 0 0
42GRB(255,255,255)255 255 255
53GRB(255,0,0)255 0 0
64GRB(0,255,0)0 255 0
75GRB(0,0,255)0 0 255
86GRB(255,255,0)255 255 0
97GRB(255,0,255)255 0 255
108GRB(0,255,255)0 255 255
119GRB(128,0,0)128 0 0
1210GRB(0,128,0)0 128 0
1311GRB(0,0,128)0 0 128
1412GRB(128,128,0)128 128 0
1513GRB(128,0,128)128 0 128
1614GRB(0,128,128)0 128 128
1715GRB(192,192,192)192 192 192
1816GRB(128,128,128)128 128 128
1917GRB(153,153,255)153 153 255
2018GRB(153,51,102)153 51 102
2119GRB(255,255,204)255 255 204
2220GRB(204,255,255)204 255 255
2321GRB(102,0,102)102 0 102
2422GRB(255,128,128)255 128 128
2523GRB(0,102,204)0 102 204
2624GRB(204,204,255)204 204 255
2725GRB(0,0,128)0 0 128
2826GRB(255,0,255)255 0 255
Sheet6
Cell Formulas
RangeFormula
E3:G28E3=LET(t," "&SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(RIGHT(C3,LEN(C3)-3),"(",""),")",""),","," ")&" ",s,SEQUENCE(,3),su,SUBSTITUTE(t," ","~",s),fi,FIND("~",su,s),f,FIND("~",SUBSTITUTE(t," ","~",s+1),s),l,LEFT(t,f),REPLACE(l,1,fi,""))
Dynamic array formulas.
You are very cordial for your explanation, although your formula is outside my basic knowledge, I will try to understand it and put it into practice, a hug!
 
Upvote 0
A slightly shorter version of my suggestion in post#6
Excel Formula:
=TRANSPOSE(FILTERXML("<k><m>"&SUBSTITUTE(SUBSTITUTE(MID(C2,FIND("(",C2)+1,100),",","</m><m>"),")","")&"</m></k>","//m"))
As always I appreciate your immense help, I would like to ask you another favor, would you be so kind to explain me a little, how your formula works? Again, thank you very much for your collaboration.
 
Upvote 0
Also, you can try this formula in J2:

=LOOKUP(999,-("("&RIGHT(C2,{2,3,4})))
Could I ask you another favor, would you be so kind to explain me a little bit how your formula works, especially the part of the comparison vector where you add a - sign and concatenate it with the RIGHT function. Thanks again!
 
Upvote 0
This part MID(C2,FIND("(",C2)+1,100) find the ( in the cell & returns everything after it to give "0,0,0)"
then the substitutes substitute the comma for the tags & removes the ) giving "0</m><m>0</m><m>0"
That is then concatenated with the starting & ending tags to give "<k><m>0</m><m>0</m><m>0</m></k>"
The Filterxml functions then converts that to an array, which is transposed so that the array spills horizontally, rather than vertically.

HTH
 
Upvote 0
This part MID(C2,FIND("(",C2)+1,100) find the ( in the cell & returns everything after it to give "0,0,0)"
then the substitutes substitute the comma for the tags & removes the ) giving "0</m><m>0</m><m>0"
That is then concatenated with the starting & ending tags to give "<k><m>0</m><m>0</m><m>0</m></k>"
The Filterxml functions then converts that to an array, which is transposed so that the array spills horizontally, rather than vertically.

HTH
Thank you very much for your clarification, I will put your explanations into practice.
A big hug!
 
Upvote 0

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