Generating permutations on three factors

alithebarman

New Member
Joined
Nov 5, 2010
Messages
7
Afternoon all.

I attempting to generate a list of possible permutations based on 3 possible factors (one factor of 227 possibilities, a second factor or 8 possibilities and a final factor of 25 possibilities). The combinations are starting to blow my mind a little.

As a brief example I'm starting with:

Code:
<table border="1">
  <tr>
    <td>Stream</td>
    <td>Level</td>
    <td>Instance</td>
  </tr>
  <tr>
    <td>BSBADM</td>
    <td>1</td>
    <td>01</td>
  </tr>
  <tr>
    <td> </td>
    <td>2</td>
    <td>02</td>
  </tr>
</table>
I would expect the result to be the following list:

  • BSBADM101
  • BSBADM102
  • BSBADM201
  • BSBADM202

If at all possible it would be very useful to update the formulas to the list of permutations changes.

Appreciate any and all comments guys!
 

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