How to fill a matrix of 18 x 9 randomly

[Msmits]

Hi,

for a bingo game, I'm looking for a way to randomly fill a matrix of 18 rows by 9 columns with only 90 numbers (1 - 90). This means there are 72 open positions (or filled with zero's).

There are some rules to be applied to fill the matrix:

• Each row can only have 5 numbers
• The first column has 9 numbers
  • in the first column number 1 - 9 are used
• 2nd till 8th column have 10 numbers
  • in the 2nd column number 10 - 19 are used
  • in the 3rd column number 20 - 29 are used
  • ...
• Last column has 11 numbers (numbers 80-90)

Anyone some thoughts on how I can do this?
I can manage to get each row only using 5 number, the right set of number in every column but I cannot manage to get the total number by column correct....

Thanks for your input.
Maarten

 

[Kenneth Hobson]

I would agree with you Rick. After 3,500 loops last night, my random routine still did not produce 18 rows with 5 cells filled in each. The best I got was 10 of 18 rows with 5 cells filled in each.