Problem with nested statements.

sam3d

New Member
Joined
Apr 4, 2013
Messages
2
Hello,

I wonder if some one can help me solve the folowing...

I keep getting this error message "The specified formula connot be entered because it uses more levels of nesting than are allowed"



=IF(AB5="","",IF((AB5=0),0,IF((AB5<=8000),0.28,IF((AB5<=9000),0.26,IF((AB5<=10000),0.255,IF((AB5<=11000),0.24,IF((AB5<=12000),0.2375,IF((AB5<=13000),0.235,IF((AB5<=14000),0.23,IF((AB5<=15000),0.2275,IF((AB5<=16000),0.225,IF((AB5<=17000),0.2225,IF((AB5<=18000),0.22,IF((AB5<=19000),0.2175,IF((AB5<=25000),0.215,IF((AB5<=30000),0.21,IF((AB5<=50000),0.205)))))))))))))))))


It's basically a labor cost expected total based on sales.

any advise would be appreciated.


-Sam.
 

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Excel Facts

Using Function Arguments with nested formulas
If writing INDEX in Func. Arguments, type MATCH(. Use the mouse to click inside MATCH in the formula bar. Dialog switches to MATCH.

Scott Huish

MrExcel MVP
Joined
Mar 17, 2004
Messages
19,952
Office Version
365, 2010
Platform
Windows
Instead of nested IFs have a look at the VLOOKUP function.
 

circledchicken

Well-known Member
Joined
Aug 13, 2011
Messages
2,932
Hi,

Another alternative might be INDEX / MATCH with a match type of -1 (finding the smallest value that is greater than or equal to lookup value), like this:

Code:
=IF(
   AB5 = "", "",
   INDEX(
     {0.205;0.21;0.215;0.2175;0.22;0.2225;0.225;0.2275;0.23;0.235;0.2375;0.24;0.255;0.26;0.28;0},
     MATCH(
      AB5,
      {50000;30000;25000;19000;18000;17000;16000;15000;14000;13000;12000;11000;10000;9000;8000;0},
      -1))
  )
You might want to move the hardcoded values to ranges on your worksheet or named ranges. For more on the MATCH function and INDEX/MATCH see:
MS Excel: MATCH Function (WS)
MATCH - Excel - Office.com
Excel Index Function and Match Function
 
Last edited:

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