VBA Help...

Jav_uk8

New Member
Joined
Jan 12, 2017
Messages
22
Hi All,

VBA help

I have a total column in row 664 (this will be variant week to week)

I need the VBA to calculate L664 / K664 but like I mentioned the above, it will not be fixed to this row every week.

What I have so far is:

Range("N1").End(xlDown).End(xlDown).Offset(2, 0).Select
ActiveCell.FormulaR1C1 = "% of Collection Rate"

Range("O1").End(xlDown).End(xlDown).Offset(2, 0).Select

Hope this makes sense?

Cheers

Jav
 

Excel Facts

Using Function Arguments with nested formulas
If writing INDEX in Func. Arguments, type MATCH(. Use the mouse to click inside MATCH in the formula bar. Dialog switches to MATCH.
Perhaps.
Code:
    .Value = "% of Collection Rate"
    .Offset(, 1).FormulaR1C1 = "=R[-2]C[-3]/R[-2]C[-4]"
End With
 
Upvote 0
How about something like
Code:
Sub DivTotals()
   With Range("L" & Rows.Count).End(xlUp)
      .Offset(, 3).Value = .Value / .Offset(, 1).Value
   End With
End Sub
 
Upvote 0
Oops, kind of missed an important part - the first line of the code.:eek:
Code:
With Range("N" & Rows.Count).End(xlUp).Offset(2, 0)
    .Value = "% of Collection Rate"
    .Offset(, 1).FormulaR1C1 = "=R[-2]C[-3]/R[-2]C[-4]"
End With
 
Upvote 0
Hi Fluff / Norie,

Unfortunately neither work - For this week the formula will be in cell 0666 (which will be the sum L664 / K664)

 
Upvote 0
How did the posted code no work?

Errors?

Formulas/values not going where expected?
 
Upvote 0
Hi Norie,

I have got the formula to work!!! :)

My problem now is how do I format the cell into a percentage cell?

My VBA is below:

With Range("M" & Rows.Count).End(xlUp).Offset(2, 0)
.Value = "% of Collection Rate"
.Offset(, 1).FormulaR1C1 = "=R[-2]C[-2]/R[-2]C[-3]"
 
Upvote 0
Try this, change the formatting. e.g decimal places, as required.
Code:
With Range("M" & Rows.Count).End(xlUp).Offset(2, 0)
    .Value = "% of Collection Rate"
    With .Offset(, 1)
        .FormulaR1C1 = "=R[-2]C[-2]/R[-2]C[-3]"
        .NumberFormat = "0.00%"
    End With
End With
 
Upvote 0

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