cheesiepoof05
Board Regular
- Joined
- Dec 30, 2010
- Messages
- 82
I am trying to come up with a formula for Column S (count of Broad Names with 1 or more 1's in the unique name count, split by field ID" which will tell me how many Broad Names are being used per Field ID. I added in the correct answer already just manually but I need to figure out a formula to replicate that.
<colgroup><col width="39" style="width: 29pt; mso-width-source: userset; mso-width-alt: 1248;">
<col width="103" style="width: 77pt; mso-width-source: userset; mso-width-alt: 3296;">
<col width="149" style="width: 112pt; mso-width-source: userset; mso-width-alt: 4768;">
<col width="115" style="width: 86pt; mso-width-source: userset; mso-width-alt: 3680;">
<col width="174" style="width: 131pt; mso-width-source: userset; mso-width-alt: 5568;">
<tbody>
</tbody>
Thank you!
O | P | Q | R | S |
Field ID | BROAD NAME | UNIQUE NAME | Unique Name Being Used (1=Yes, 0=No) | Count of Broad Names With 1 or more 1's in the Unique Name Count, Split by Field ID |
400 | DOGS | German Shepherd | 1 | 3 |
400 | DOGS | Poodle | 0 | 3 |
400 | CATS | Persian | 1 | 3 |
400 | CATS | Siamese | 1 | 3 |
400 | CATS | Abyssinian | 0 | 3 |
400 | REPTILES | Crocodile | 0 | 3 |
400 | REPTILES | Chameleon | 0 | 3 |
400 | AMPHIBIANS | Frog | 1 | 3 |
573 | BLUES | Carolina | 1 | 2 |
573 | BLUES | Cobalt | 1 | 2 |
573 | BLUES | Turquoise | 0 | 2 |
573 | REDS | Magenta | 0 | 2 |
573 | REDS | Candy Apple | 0 | 2 |
573 | REDS | Auburn | 0 | 2 |
573 | REDS | Wine | 0 | 2 |
573 | GREENS | Avocado | 1 | 2 |
573 | GREENS | Mint | 0 | 2 |
573 | GREENS | Chartreuse | 1 | 2 |
Thank you!