Excel VBA Function to measure cycle through range and measure multiple correlations

joejackson123

New Member
Joined
Oct 27, 2017
Messages
16
I'm trying to create an Excel VBA function that cycles through a <code>cycle_range</code> and calculates the correlation each range of 5 cell entries within that range to a <code>base_range</code> of 5 cell entries. The function should return the maximum correlation in the cycle_range. For example, the following data should return the 0.506..... output, as the second set of cycle range numbers, <code>7, 8, 9, 0, 8</code>, have that correlation to the base range, which is the highest correlation:

<code>
</code>
Code:
<code>cycle range     base range       output
     4              3          0.506253796
     7              7   
     8              3   
     9              2   
     0              9   
     8      
     5      
     4  </code>

The code I have thus far is below, it doesn't work. There is very clearly a problem with adding rng and elements together from cycle_range, but not sure what to do:

Code:
<code>Function best_correl(correl_length As Double, base_range As Range, cycle_range As Range)


Dim i As Double
Dim rng As Range
Dim cycle_range_length As Double
Dim element As Variant
Dim max_correl As Double
Dim curr_correl As Double


cycle_range_length = cycle_range.Count - correl_length


For i = 1 To cycle_range_length

    For element = 1 To correl_length
        rng = rng + element
    Next element

    curr_correl = WorksheetFunction.Correl(base_range, rng)

    If curr_correl > max_correl Then
        max_correl = curr_correl
    End If

Next i


best_correl = max_correl


End Function</code>
As always, any advice is very much appreciated, I'm having a tough time with this one. Thank you!
P.S. I cribbed some stuff from here - vba pass a group of cells as range to function
 
Last edited:

Excel Facts

Select all contiguous cells
Pressing Ctrl+* (asterisk) will select the "current region" - all contiguous cells in all directions.
try this, I changed it to a subroutine to allow me to test it easily, also I wrote the answers out to see it was working:
Code:
Sub test2()
 Dim base_range As Range
 Dim cycle_range As Range
Set base_range = Range("B2:B6")
Set cycle_range = Range("A2:A9")
Dim inarr As Variant
Dim cycler As Variant
Dim temparr() As Variant


inarr = base_range
cycler = cycle_range
baselen = UBound(inarr)
cyclen = UBound(cycler)
ReDim temparr(1 To baselen, 1 To 1)


Dim i As Double
Dim max_correl As Double
Dim curr_correl As Double




Numits = cyclen - baselen






For i = 1 To Numits


     For j = 1 To baselen
      temparr(j, 1) = cycler(i + j - 1, 1)
     Next j
    curr_correl = WorksheetFunction.Correl(inarr, temparr)
     Cells(i + 1, 10) = curr_correl
    If curr_correl > max_correl Then
        max_correl = curr_correl
    End If


Next i




best_correl = max_correl




End Sub
 
Upvote 0
Here's an alternate piece of code that I put together; this works. Now, though, my question is if I can have it return the LOCATION of the max_correl in the range - i.e., if the second iteration is the highest correlation, best_correl is returned as "2". Any help is appreciated, thanks!

Code:
 <code>Function best_correl(correl_length As Double, base_range As Range, cycle_range As Range)

    Dim c As Range
    Dim cycle_range_length As Long
    Dim max_correl As Double
    Dim curr_correl As Double

    cycle_range_length = 1 + (cycle_range.Count - correl_length)

    For Each c In cycle_range.Resize(cycle_range_length, 1).Cells
        curr_correl = WorksheetFunction.Correl(base_range, c.Resize(correl_length, 1))
        If curr_correl > max_correl Then max_correl = curr_correl
    Next c

    best_correl = max_correl

End Function</code>
 
Upvote 0
If you used the code that I provided then all you need to do is save the value of the loop index I instead of the value e.g:
change this line:
Code:
max_correl = curr_correl
to
Code:
max_correl = i
with your code it is more difficult
but I suggest you try using something like (untested)
Code:
max_correl=c.row
 
Upvote 0

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